It depends on the base, but for either e or 10, it is irrational.
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Yes. Take any rational number p. Let a = any number that is not a power of 10, so that log(a) is irrational. and let b = p/log(a). log(a) is irrational so 1/log(a) must be irrational. That is, both log(a) and log(b) are irrational. But log(a)*log(b) = log(a)*[p/log(a)] = p which is rational. In the above case all logs are to base 10, but any other base can be used.
36 is a rational number
Irrational numbers are precisely those real numbers that cannot be represented as terminating or repeating decimals. Log 216 = 2.334453751 terminates and is therefore not irrational.
No. An irrational number cannot be expressed as a/b where a and b are integers, b not zero. 18 = 18/1 = 36/2 = -36/-2 etc.
The square of 36 is 1,296 ... rational.The square root of 36 is 6 ... also rational.