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Q: Is the product of 3 consecutive numbers divisible by 3?
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If you take the 3 numbers in any consecutive trio and multiply them together to get a new number that new number will always be a multiple of 6 why is this?

18


Can you find three consecutive natural numbers none of which is divisible by 3?

No. Every third consecutive natural number is divisible by 3.


The sum of 3 consecutive odd numbers is 59 what are the numbers?

The sum of three consecutive odd numbers must be divisible by 3. As 59 is not wholly divisible by 3 the question is invalid. PROOF : Let the numbers be n - 2, n and n + 2. Then the sum is 3n which is divisible by 3. If the question refers to three consecutive numbers then a similar proof shows that the sum of these three numbers is also divisible by 3. Again, the question would be invalid.


You are a 3 digit multiple of 10 you are the product of two consecutive numbers you are divisible by 6 and 7 the sum of your digits is 6 what is your number?

420


Is the product of any 3 consecutive whole number is divisible by 6?

No.


What one-digit number is the product of two consecutive prime numbers?

There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)


The product of 3 consecutive odd numbers make 6873 what is it?

There is no set of 3 consecutive odd numbers whose product is 6,873. However, there is a set of 3 consecutive odd numbers whose sum is 6,873: 2289, 2291, and 2293.


What 3 consecutive composite numbers whose product of 192?

There are no such numbers. The smallest set of three consecutive composite numbers is {8, 9, 10} and the product of these numbers is 720.


Why is the product of 3 consecutive integers always divisible by 6?

Let the three integers be, n, (n + 1), and (n + 2) Then at least one of these numbers is even and therefore has a factor of 2. And one of the numbers is divisible by 3 **. Therefore the product has factors of 2 and 3 and is thus divisible by 2 x 3 = 6. ** Either n is divisible by 3. Or, n leaves a remainder of 1 when divided by 3 in which case (n + 2) is divisible by 3. Or, n leaves a remainder of 2 when divided by 3 in which case (n + 1) is divisible by 3.


The product of three consecutive numbers is 60 What are the 3 numbers?

3 x 4 x 5 = 60 The three consecutive numbers are 3, 4, and 5.


Is the sum of three consecutive whole numbers divisible by three?

5+2+1=8 and 8 is not divisible by 3.


The product of which 3 consecutive odd numbers 6783?

17,19,21