No, the Sum of two reciprocals isn't 1. However, the PRODUCT of two reciprocals is 1. For example, if you multiply 1/2 with 2/1, you'd multiply the two numeraters, which would be 1X2=2, and the two denominators, which is 2X1=2. this would cause the answer to be 2/2, or 1.
It is 0.5
Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2
Every pair of mutual reciprocals has a product of 1 .
If you multiply two reciprocals, their product must be 1.
No, the Sum of two reciprocals isn't 1. However, the PRODUCT of two reciprocals is 1. For example, if you multiply 1/2 with 2/1, you'd multiply the two numeraters, which would be 1X2=2, and the two denominators, which is 2X1=2. this would cause the answer to be 2/2, or 1.
Suppose the two numbers are x and y. Then, the sum of THEIR reciprocals is 1/x + 1/y = y/xy + x/xy = (y + x)/xy = 7/25
1/x + 1/y = (y+x)/xy But y + x = sum = 150, and xy = product = 40 So sum of reciprocals = 150/40 = 3.75
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
Oh, dude, the sum of the reciprocals of all the divisors of 6 is 2. Like, you take the divisors of 6, which are 1, 2, 3, and 6, and then you flip them upside down and add them all up. So, 1/1 + 1/2 + 1/3 + 1/6 = 2. Easy peasy, lemon squeezy!
It is 0.5
sannie
2 and 1/2 and 2 and 4/5, respectively.
Well, honey, the reciprocal of a number is just 1 divided by that number. So, the reciprocals of 6 and 8 are 1/6 and 1/8. Add those bad boys up, you get 7/24. Flip that sum upside down and you've got yourself the reciprocal of the sum of the reciprocals of 6 and 8, which is 24/7. Math can be a real rollercoaster, but we're just along for the ride!
No. That only works with products.
reciprocal of the sum of the reciprocals.
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