A general form for finding a given number of combinations for a chosen sub-set of numbers from a set is
Cr(n, r) = n!/r!(n-r)!
This indicated the difference between a haploid and a diploid, or rather if a cell has 1 or 2 sets of chromosomes. N = Haploid (A gamete or sex cell) 2N = Diploid (Somatic cell)
chromosome segregationIf the character is governed by a single allele and it is dominant, than its probability to be in the gamete is 75%.
Well if you're talking about mitosis, the differences are insignificant. If you're talking about meiosis, then the differences is that DNA replication only occurs prior to prophase 1 and does not occur prior to prophase 2 in order to produce haploid gamete cells, rather than diploid somatic cells. I hope this was detailed enough. There are more differences, but I doubt you need to know them, based on your question.
The four gamete combinations arise from the segregation of alleles during meiosis. If considering a dihybrid cross (e.g., AaBb), the combinations are AB, Ab, aB, and ab. This occurs due to the independent assortment of the alleles for different traits, resulting in these four unique gametes. Each combination represents a different allele configuration that can contribute to offspring genetic variation.
It gives one of the gametes an extra chromosome and leaves the other gamete with one less chromosome.
An ovum is a haploid gamete. It contains one set of chromosomes (23 in humans) and is produced through meiosis from a diploid cell. When the ovum fertilizes with a sperm cell, it forms a diploid zygote with a full set of chromosomes.
A gamete has half the number of chromosomes of the somatic (diploid) cell. Therefore a zebra gamete would have 25 chromosomes if 50 is the diploid number.
The embryo and endosperm of the pine nut are diploid. The embryo is formed from the fusion of a male gamete (sperm) and a female gamete (egg), both of which are haploid, resulting in a diploid zygote. The endosperm is also formed from a fusion of a male gamete and a central cell in the female gametophyte.
As a gamete, it's haploid.
A gamete is haploid (1N) so 'Aa' & 'AA' are diploid and during cell division (mitosis) gametes are formed and then 2 gametes merge together to make a diploid (think of sperm and egg, each is haploid or 1N, when fertilization occurs the egg and sperm form 1 cell that is 2N or diploid). So the possible gametes for 'Aa' would be 'A' & 'a' while for 'AA' the only gametes possible are 'A' If the question is asking what the possible gametes are for 'AaBB' the haploid (gamete) can be 'AB' or 'aB'
Four gamete types can be formed from the diploid individual TtPp. This is because during meiosis, the two parent alleles for each gene (Tt and Pp) will segregate into separate gametes, resulting in four possible combinations of alleles (TP, Tp, tP, tp).
A gamete would be haploid, containing half the number of chromosomes compared to a diploid cell. Therefore, a gamete of this organism would be expected to contain 29 chromosomes.
If all of the chromosomes fail to separate in meiosis, then nondisjunction can result in a diploid gamete. This is a type of chromosomal mutation. In animals, a zygote produced from the union of a mutated diploid gamete and a normal haploid gamete will have triploidy, which is lethal. In plants, this is not necessarily lethal.
The chromosome number in each gamete will be 14, which is half of the diploid number. During meiosis, the diploid cell undergoes two rounds of cell division to produce four haploid gametes, each containing 14 chromosomes.
Human muscle cells are diploid.All human cells are diploid except for gametes (sperms and ova) and the cells that divide to form them (secondary spermatocytes and secondary oocytes).
In a gamete (sex) cell, there are 23 chromosomes. A gamete is a haploid, or n, whereas a somatic (normal) cell is a diploid, or 2n, and has 46 chromosomes.
You'd be a multicellular diploid adult (2n=46)