The expression "7y27 y4" does not represent a standard mathematical inequality. It appears to be a combination of numbers and variables without clear operators or relational symbols (like <, >, ≤, or ≥). If you intended to write an inequality, please clarify the expression, and I can help you interpret it correctly.
x=y4 /2
The inequality you provided seems to be incomplete or incorrectly formatted. However, if we assume you're referring to an inequality such as (2xy < 4), then ordered pairs ((x, y)) that satisfy this would include those where the product of (xy) is less than 2, such as ((1, 1)), ((0, 0)), or ((2, 0)). To find specific solutions, you would substitute values for (x) and solve for (y) to check if they satisfy the inequality.
y4
y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2
x2 + y4 + x4 +y2 = x6 + y6unless you know what x and y are.* * * * *x2 + y4 + x4 + y2 ??I don't believe that this expression can be factorised or otherwise simplified.It certainly does not equal x6 + y6,for all x and all y:for example, if x = y = 1, thenx2 + y4 + x4 + y2 = 4, whilstx6 + y6 = 2;thus, they are two manifestly unequal quantities.
The GCF is y4
x=y4 /2
4x-y4 what = 0
The simplest equation would be y4 = 0
(x2 + y2)(x + y)(x - y) = x4 - y4.
The inequality you provided seems to be incomplete or incorrectly formatted. However, if we assume you're referring to an inequality such as (2xy < 4), then ordered pairs ((x, y)) that satisfy this would include those where the product of (xy) is less than 2, such as ((1, 1)), ((0, 0)), or ((2, 0)). To find specific solutions, you would substitute values for (x) and solve for (y) to check if they satisfy the inequality.
-2
y + y4 = y5 , possibly. Except that conventionally, the number (or coefficient) would be written first. y + y4 = y*(1 + y3) = y(1 + y)*(1 - y + y2)
y4
y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2
y4 - 256 = (y2 - 16)(y2 + 16) = (y - 4)(y + 4)(y2 + 16)
sqrt(100x4y4) = sqrt(100)*sqrt(x4)*sqrt(y4) = 10*x2*y2