0
What else can I help you with?
How can you do x4-y4?
(x2 + y2)(x + y)(x - y) = x4 - y4.
X2 plus y4 plus x4 plus y2?
x2 + y4 + x4 +y2 = x6 + y6unless you know what x and y are.* * * * *x2 + y4 + x4 + y2 ??I don't believe that this expression can be factorised or otherwise simplified.It certainly does not equal x6 + y6,for all x and all y:for example, if x = y = 1, thenx2 + y4 + x4 + y2 = 4, whilstx6 + y6 = 2;thus, they are two manifestly unequal quantities.
What is the square root of 40 x12 y9?
√(40 x12y9) = 6.3246√(y)* x6 *y4 or 6.3246x6y4.5 ■
X4 plus y4 divided by x plus y?
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
How do you express x4 plus y4 if given x plus y equals a xy equals b?
(x + y)2 = x2 + 2xy + y2 So x2 + y2 = (x + y)2 - 2xy = a2 - 2b Then (x2 + y2)2 = x4 + 2x2y2 + y4 So x4 + y4 = (x2 + y2)2 - 2x2y2 = (a2 - 2b)2 - 2b2 = a4 - 4a2b + 4b2 - 2b2 = a4 - 4a2b + 2b2
What is the greatest common factor of x4 y4 x10 y6 x9 x4?
18xy is the GCF of 72x2y and 18xy
What is the answer for x plus y to 4th power?
(x+y)4 = (x2+2xy+y2)2 = x4+4x3y+6x2y2+4xy3+y4
Factor completely 32y4 -2x4 y4?
2y4(16 - x4) = 2y4 (4 + x2)(4 - x2) = 2y4(4 + x2)(2 + x)(2 - x)
How can you find irrational number between any two number?
There are infinitely many irrational numbers between any two numbers - rational or irrational.Suppose x and y are two irrational numbers.Consider x2 and y2. Is there any integer between them that is not a perfect square? If so, the square root of that number is an irrational between x and y.If not, consider x3 and y3 and look for an integer between them that is not a perfect cube. If there is then the cube root of that number will meet your requirements.If not, try x4 and y4 and then x5 and y5 etc. In a school exercise you are extremely unlikely to have to go as far as the cubes!
What is the gcf of y4 y8 y9?
The GCF is y4
Can you completely factor x32 - y32?
0
How do you solve y4-84 plus 5y2?
You cannot solve it since only one side of an equation is given. If the equation was y4 + 5y2 - 84 = 0 then y4 + 12y2 - 7y2 - 84 = 0 or y2*(y2 + 12) - 7*(y2 + 12) = 0 or (y2 - 7)*(y2 + 12) = 0 then y2 = 7 or y2 = - 12 y = +or- sqrt(7) and, if you are in the complex domain, also y = +or- i*sqrt(12) where i is the imaginary square root of -1.
