3x2 + 36x + 81 = 3(x2 + 13x + 27)
(X-9)2
The answer to the question is: (2p+1)(2p+81) for Equation 4p^2+164p+81 P.S ^ is exponent
(3X + 9) (X + 9)
9
81.
Yes!
(p - 9)(p - 9)
3x2 + 36x + 81 = 3(x2 + 13x + 27)
(X-9)2
The answer to the question is: (2p+1)(2p+81) for Equation 4p^2+164p+81 P.S ^ is exponent
(3X + 9) (X + 9)
If a trinomial is a perfect square, then the discriminant will equal 0. The discriminant is equal to B^2-4AC. The variables come from the standard form of a quadratic which is Ax^2+Bx+C In this problem, A=81, B=-72, and C=16 so the discriminant is: (-72)^2-4(81)(16)=5,184-5,184=0 so this is a perfect square trinomial. To factor, notice that 81=9^2 and 16=4^2, so 81x^2=(9x)^2. We can then factor the trinomial into (9x+4)(9x-4)
9
square root of 81 is 9...and plus 32 is 41.so the answer is 41
√81 + √196 = 23
A trinomial is a polynomial with three unlike terms. Ex3n + 7x + 8y6xy is a trinomial?false . . . .A+