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Algebra

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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Q: X2 plus 18x plus 81 is this a trinomial?
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Is this trinomial a trinomial square x2-18x plus 81?

x2-18x+81 = (x-9)(x-9) when factored


Factor the trinomial x2-18x plus 81?

(X-9)2


Factor the trinomial below Enter each factor as a polynomial in descending orderx2 plus 18x plus 45?

x2 + 18x + 45 = (x + 15)(x + 3).


What is the factorization of this trinomial 3x2 plus 36x plus 81?

3x2 + 36x + 81 = 3(x2 + 13x + 27)


What number must you add t complete the square x2 plus 18x equals -13?

81. To complete the square, halve the coefficient of the x term (18/2 = 9) and add the square of this (92 = 81) to both sides: x2 + 18x = -13 ⇒ x2 + 18x + 81 = -13 + 81 ⇒ (x + 9)2 = 68


How do you factor x2 plus 18x-50?

x2 + 18x - 50 does not have rational factors.


What is y equals x2 18x plus 52 in vertex form?

Y = X2 + 18X + 52 set to 0 X2 + 18X + 52 = 0 subtract 52 from each side X2 + 18X = - 52 now, halve the coefficient of the variable term (18), square it and add it to both sides X2 + 18X + 81 = - 52 + 81 now, factor on left and gather terms on right (X + 9)2 = 29 (X + 9)2 - 29 = 0 ---------------------------vertex form


What is x2 plus 20x plus 10c?

A trinomial.


What is y equals x2-18x plus 52 in vertex form?

y=x2-18x+52First off, this does not factor cleanly, but even if it did it would not help us. We must complete the square to yield a perfect-square trinomial (a trinomial that can be written in the form (x-a)2 where a is a real number.To do this, halve the coefficient of the single-x term (for this case, the term 18x) and square it.18/2=992=81The result of this process can be added to the two terms involving x to get a perfect square trinomial. For instance, the trinomial that would result would be:x2-18x+81=(x-9)2However, there is already 52 of that 81 that is needed present, so in reality, you only need to add 29 (81-52=29) to the right side of the equation to get a perfect-square trinomial. Whatever is done to one side of the equation must be done to the other side, so since you added 29 to the right side, you must add 29 to the left side, giving you:y+29=x2-18x+52+29y+29=x2-18x+81y+29=(x-9)2y=(x-9)2-29This is in vertex form, you can see that the vertex is at (9,-29)


Is this trinomial a trinomial square x2 plus 14x plus 49?

x2+14x+49 = (x+7)(x+7) when factored


What binomial is a factor of this trinomial x2 plus 8x plus 16?

x + 4


How do you factor out 3x2 plus 54x plus 243?

Divide all terms by 3 and so x2+18x+81= (x+9)(x+9) when factored

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