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How do you factorise x3 plus xy-x2y2?
x3+xy-x2y2=x(x2+y-xy2)
What is the GCF x to the second power and y then xy and to the second power?
If that's x2y and xy2, the GCF is xy.
Combine like terms of -5xy2 plus 12xy2?
-5xy2 + 12xy2 = (-5 + 12)xy2 = 7xy2
Is 2xy and 3yx are not like terms?
No, (2xy) and (3yx) are actually like terms. In algebra, like terms are terms that have the same variable factors raised to the same powers. Since (yx) is equivalent to (xy), both terms can be combined or simplified together, resulting in (5xy).
What are the terms of 4xy 3xy-3xy 2xy?
The expression (4xy - 3xy + 2xy) consists of three terms: (4xy), (-3xy), and (2xy). Each term is a product of the coefficient (a number) and the variable part, which in this case is (xy). The coefficients are 4, -3, and 2, respectively. To combine the like terms, you would simplify the expression to ( (4 - 3 + 2)xy = 3xy).
What is the GCF of x2y and xy2?
The GCF is xy
HCF of x2 y and xy2?
xy
How do yu do xy 2 to the power over xy?
If you mean: xy2/xy then it can be simplified to y
What is the greatest common factor of x2y and xy2?
xy
How do you factorise x3 plus xy-x2y2?
x3+xy-x2y2=x(x2+y-xy2)
What is the GCF x to the second power and y then xy and to the second power?
If that's x2y and xy2, the GCF is xy.
What is like terms in polynomial?
They are terms in which a variable is raised to the same power (index) in both terms. So x2y and -27x2y are like terms but not xy2.
What is the greatest common factor of x2y xy2?
To find the greatest common factor of x^2y and xy^2, we need to determine the highest power of each variable that is common to both terms. In this case, the common factors are x and y. The highest power of x that is common to both terms is x^1, and the highest power of y that is common to both terms is y^1. Therefore, the greatest common factor of x^2y and xy^2 is xy.
Combine like terms of -5xy2 plus 12xy2?
-5xy2 + 12xy2 = (-5 + 12)xy2 = 7xy2
How do you simplify 7xy-xy 3xy?
4
Collect like terms 3xy plus xy-4x plus x?
-1
How do you do variables question?
xy2
