y = x2 or y = x +2, both are functions
sorry, it is wrong the answer is : y=k/x2(square) {when y = x we will write y as x and leave x2(square) alone. like this: x=120/x2(square) x multiply by x2(square) is x3(cube) so cube root of 120 = x so x is 4.93
(x-y)2 is a square so (x-y)2 >= 0 expanding, x2 - 2xy + y2 >= 0 so x2 + y2 >= 2xy or 2xy <= x2 + y2
(x+y)2 = x2 + 2xy + y2
x2 + y - 49 = 0y = -x2 + 49First, plot the graph of y = -x2, with a vertex (0, 0), then translate it 49 units up. The vertex becomes (0, 49), which is a maximum point (the parabola opens downward).Or make a table to obtain several corresponding y-values for x = -3, -2, -1, 0, 1, 2, 3. Plot the points (x, y), and draw the graph of y = -x + 49.
The GCF is 2xy.
x3+xy-x2y2=x(x2+y-xy2)
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
3 * 3 * 5 * x * y * y = 45xy2
The compound with the formula XY2 consists of one atom of element X and two atoms of element Y.
15x2y2-9xy3 As x2y2 = x xy2 and xy3 = xy2 y then xy2 is in both term you can first factorize 15x2y2-9xy3 = xy2(15x-9y) as 15=3x5 and 9=3x3 15x2y2-9xy3 = 3xy2(5x-3y) and that it !
Y = X2 Inverse. Y = 1/X2 ======
If you mean: xy2/xy then it can be simplified to y
7
If that's x2y and xy2, the GCF is xy.
The domain of y = x2 is [0,+infinity]
If you mean y = x2, then yes, it is nonlinear.