xy
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y = x2 or y = x +2, both are functions
sorry, it is wrong the answer is : y=k/x2(square) {when y = x we will write y as x and leave x2(square) alone. like this: x=120/x2(square) x multiply by x2(square) is x3(cube) so cube root of 120 = x so x is 4.93
(x-y)2 is a square so (x-y)2 >= 0 expanding, x2 - 2xy + y2 >= 0 so x2 + y2 >= 2xy or 2xy <= x2 + y2
(x+y)2 = x2 + 2xy + y2
x2 + y - 49 = 0y = -x2 + 49First, plot the graph of y = -x2, with a vertex (0, 0), then translate it 49 units up. The vertex becomes (0, 49), which is a maximum point (the parabola opens downward).Or make a table to obtain several corresponding y-values for x = -3, -2, -1, 0, 1, 2, 3. Plot the points (x, y), and draw the graph of y = -x + 49.