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Yes, as x-y2=0
No. A simple example of this is y = x2; the inverse is x = y2, which is not a function.
Yes
x2 - y2 = (x + y)(x - y) is an identity, not a function.
No, because there is more than one solution: y2 = x2 y = ±(x2)1/2 y = ±x Because there are multiple solutions for a single value of x, this does not qualify as a function.