No.
f(x) = 2x2 + 4x - 7
y = 2(x - 1)2 + 3 y = 2(x - 1)(x - 1) + 3 y = 2(x2 - 2x + 1) + 3 y = 2x2 - 4x + 2 + 3 y = 2x2 - 4x + 5
2x2 + 3x - 20 = (x + 4)(2x - 5).
y=2x2-3x2-12x+5=0
No.
f(x) = 2x2 + 4x - 7
y = 2(x - 1)2 + 3 y = 2(x - 1)(x - 1) + 3 y = 2(x2 - 2x + 1) + 3 y = 2x2 - 4x + 2 + 3 y = 2x2 - 4x + 5
y=2x2+5. Plug in 0 for x, and you get y=2(0)^2 +5 =0+5=5. 5 is the minimum value for y.
2x2 + 3x - 20 = (x + 4)(2x - 5).
y=2x2-3x2-12x+5=0
Assuming the missing symbol there is an equals sign, then we have: y - 2x2 - 4x = 4 We can find it's vertex very easily by solving for y, and finding where it's derivative equals zero: y = 2x2 + 4x + 4 y' = 4x + 4 0 = 4x + 4 x = -1 So the vertex occurs Where x = -1. Now we can plug that back into the original equation to find y: y = 2x2 + 4x + 4 y = 2 - 4 + 4 y = 2 So the vertex is at the point (-1, 2)
determine whether each relation is a function y equals -8
y = x This is a line and a function. Function values are y values.
-2x2 + 9x - 12 = 0Then apply the quadratic formula.
B- It is a many-to-one function
-5