(This is relative)
Are you a massively awesome, super genius, hyper-smart, dedicated student? No? Then yes it will be a challenge. I'm not saying it's impossible (some would) but it's not one of those thing that you can get by doing you work at lunch.
Say you get a perfect TOK and EE score, then you only need a 37 points, which you can get by getting five 6s and one 7 (IB gives a 7 to only the top 5% of the people who took the course); or if you are just not-awsome at a subject and get a 5, you can make it up by getting a second 7, so there is some flexibility.
As a friendly advice, there is nothing more frustrating than getting, say, a 4 when you were one point away from a 5, you feel bad, and it is bad, you were a 5-student that colleges will see as a 4-student just because you forgot to divide by 2, or the year of the Great Leap Forward, etc. So, always stay well away from cut off lines (unless it is the upper one, in which case you may wish to study an extra 20min before the test).
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as a2+b2=(a+ib)(a-ib), b2+2=[b - i sqrt(2)] [b + i sqrt(2)]
It already is in the form a+ib. a = root 7, the b=1 (i.e 1 x i ).
No
If you have a complex function in the form "a+ib", the (complex) conjugate is "a-ib". "Conjugate" is usually a function that the original function must be multiplied by to achieve a real number.
Numbers of the form a + ib (where i = -11/2; a and b are real numbers) are called complex numbers.For any two complex numbers (a+ib) and (c+id):Addition:(a+ib) + (c+id) = (a+c) + i(b+d)So, -8i-7i = (-8-7)i = -15i