Q: What is conjugate function?

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The conjugate of 6 + i is 6 - i.

the conjugate 7-2i

How about "-i" since "i" is just "0 + i" so the conjugate should be "0 - i" or "-i"

semi conjugate diameter of ellipse

If you are referring to conjugate acids and bases, a conjugate acid is an acid that can donate a H+ in order to form a conjugate base. For example, HCl can donate it's H+ and create the conjugate base Cl-. On the other hand, a conjugate base would just be the opposite where chloride could add a hydrogen in order to create the conjugate acid.

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No, HCl and sodium citrate do not form a buffer system together because they do not function as a conjugate acid-base pair. In a buffer system, there needs to be a weak acid and its conjugate base, or a weak base and its conjugate acid, to maintain a stable pH.

The conjugate acid of ClO- is HClO. The conjugate acid of HClO is ClO2. The conjugate acid of HCI is H2Cl. The conjugate acid of Cl- is HCl. The conjugate acid of ClO is HClO2.

The conjugate base and conjugate acid for HS04 is: Conjugate acid is H2SO4 Conjugate base is SO42

"Conjugate" usually means that in one of two parts, the sign is changed - as in a complex conjugate. If the second part is missing, the conjugate is the same as the original number - in this case, 100.

The conjugate acid of NO2- is HNO2 (nitrous acid).

The conjugate acid of LiOH is considered Li+.

The conjugate acid of H2O is H3O+ (hydronium ion). When an acid donates a proton, it forms its conjugate base, and when a base accepts a proton, it forms its conjugate acid.

The conjugate of 6 + i is 6 - i.

It depends on what the denominator was to start with: a surd or irrational or a complex number. You need to find the conjugate and multiply the numerator by this conjugate as well as the denominator by the conjugate. Since multiplication is by [conjugate over conjugate], which equals 1, the value is not affected. If a and b are rational numbers, then conjugate of sqrt(b) = sqrt(b) conjugate of a + sqrt(b) = a - sqrt(b), and conjugate of a + ib = a - ib where i is the imaginary square root of -1.

The conjugate base of NH3 is NH2-, formed by removing a proton (H+) from NH3.

The conjugate base of HSO3- is SO32-.

the conjugate 7-2i