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As x goes to infinity, the limit does not exist.

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Q: Limit of negative 1 raised to x?
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Related questions

What is the answer to limit as x approaches infinity of e raised-x squared?

limit x tends to infinitive ((e^x)-1)/(x)


What is 2 raised to the negative one third power multiplied by 4 raised to the negative one third power?

(2)-1/3 x (4)-1/3 = (2 x 4)-1/3 = (8)-1/3 = 1/81/3 = 1/2


When is a negative number raised to an odd power negative?

It is always negative when raised to an odd power and always positive when raised to an even power -2 to the third power = -2 x -2 x -2 = -8 -2 to the fourth power = -2 x -2 x -2 x -2 = +16


What does 10 to the negative 73 power equal?

Any number x raised to a negative power -y is equivalent to the reciprocal of x raised to y. So, 10-73 would be the fraction 1 over the number 1 with 73 zeroes after it. A very small number indeed!


Is it true that infinity goes both ways?

Yes, ∞ and -∞ both exist as distinct entities. If I take the limit of 1/x as x approaches 0 from the positive side, I get ∞. On the other hand if I take the limit of 1/x as x approaches 0 from the negative side, I get -∞.


What is the limit of x as it approaches infinity for e to the negative 2x divided by the square root of 1-x squared?

1


What is the limit of x to the 4-1 divided by x-1 as x approaches 1?

The limit is 4.


What is the answer of -x5y2?

The answer to -x^5y^2 is a negative number raised to the fifth power multiplied by y raised to the second power. It cannot be simplified further without knowing the specific values of x and y.


Does a negative plus a negative equal a positive?

a negative number plus a negative number is negative. here is a proof.(-x)+(-x)(-1)x+(-1)x-1(x+x)-1(2x)-2xa negative number times a negative number is positive though.


What is limit as x approaches 0 of cos squared x by x?

The limit of cos2(x)/x as x approaches 0 does not exist. As x approaches 0 from the left, the limit is negative infinity. As x approaches 0 from the right, the limit is positive infinity. These two values would have to be equal for a limit to exist.


What are the negative reciprocals of each other?

The negative reciprocal of a non-zero number x, is -1/x. And the negative reciprocal of that is -1/(-1/x) = -1*(x/-1) = x


Which number is further from 0?

There in so limit. If x is any positive number, then (x + 1) is further from 0.If y is any negative number, then (y - 1) is further from 0.