Q: Mathematical formula for volume of truncated tetrahedron?

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V=h/3 (axa + axb + bxb)

A hollow truncated cone is a geometric shape that is cone-shaped. The formula to calculate the volume is s^2=h^2 + (R-r)^2.

The formula for the volume of a truncated square pyramid with height h, and top edge a cm and bottom edge b cm is V = 1/3*(a2 + ab + b2)*h.

If the area of the base of the tetrahedron is A square units and the vertical height is h units, then the volume is V = 1/3*A*h cubic units. If the tetrahedron is regular, with sides of length of length s units, then V = sqrt(2)/12*s3 cubic units.

The volume(cm3) of a tetrahedron is 1/3 (area of the base)X height

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V=h/3 (axa + axb + bxb)

A hollow truncated cone is a geometric shape that is cone-shaped. The formula to calculate the volume is s^2=h^2 + (R-r)^2.

A formula is a string of letters and numbers and other mathematical characters. It has no volume.

no

It is a set of mathematical operations which have to be carried out, using some measures of an object and possibly mathematical constants, to find the total amount of space which an object occupies.

V = (1/3*Pi*h) * (R12 + R22 + R1*R2) Where R1 and R2 are the radii of the bases, and h is equal to the height of the truncated cone.

6s2

The formula for the volume of a truncated square pyramid with height h, and top edge a cm and bottom edge b cm is V = 1/3*(a2 + ab + b2)*h.

If the area of the base of the tetrahedron is A square units and the vertical height is h units, then the volume is V = 1/3*A*h cubic units. If the tetrahedron is regular, with sides of length of length s units, then V = sqrt(2)/12*s3 cubic units.

The volume(cm3) of a tetrahedron is 1/3 (area of the base)X height

The individual who earlier posted an answer provided the mathematical formula for volume -.-

The density of an object is the ratio of its mass to its volume. Equivalently, it is its mass per unit volumes. In mathematical terms, Density = Mass/Volume