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V=h/3 (axa + axb + bxb)
A hollow truncated cone is a geometric shape that is cone-shaped. The formula to calculate the volume is s^2=h^2 + (R-r)^2.
The formula for the volume of a truncated square pyramid with height h, and top edge a cm and bottom edge b cm is V = 1/3*(a2 + ab + b2)*h.
If the area of the base of the tetrahedron is A square units and the vertical height is h units, then the volume is V = 1/3*A*h cubic units. If the tetrahedron is regular, with sides of length of length s units, then V = sqrt(2)/12*s3 cubic units.
The volume(cm3) of a tetrahedron is 1/3 (area of the base)X height