The volume of a tetrahedron is one-sixth of the volume of a parallelepiped because a tetrahedron can be thought of as a pyramid with a triangular base. When a tetrahedron is inscribed within a parallelepiped, it occupies one-sixth of the space defined by the parallelepiped's volume. Since a parallelepiped can be divided into six such tetrahedra, this means the volume of the tetrahedron is 1/6 of the parallelepiped. However, if the parallelepiped is defined by its full height and includes the whole base area, the tetrahedron's volume is one-sixteenth of the total volume when considering the full dimensions of the parallelepiped.
Volume of a parallelogram = cross-section area times length
The volume(cm3) of a tetrahedron is 1/3 (area of the base)X height
Cubes, Cuboids, Spheres, Ellipsoids. Pyramids, and name suffixed with 'hedron'.e.g. 'Tetrahedron. Parallelopiped, Rhombohedron, Prism, Trapezohedron, Cylinder. 'Lemon'(very special form of ellipsoid), , Hyperboloid
Trying to figure this out too...
V = 1/3 * base area * height.
A cuboid, a pentagonal pyramid, a di-tetrahedron, a parallelopiped are some possibilities.
Volume of a parallelogram = cross-section area times length
The volume(cm3) of a tetrahedron is 1/3 (area of the base)X height
A parallelopiped. A cuboid is a special case of a parallelopiped, and a cube is a special case of a cuboid.
Cubes, Cuboids, Spheres, Ellipsoids. Pyramids, and name suffixed with 'hedron'.e.g. 'Tetrahedron. Parallelopiped, Rhombohedron, Prism, Trapezohedron, Cylinder. 'Lemon'(very special form of ellipsoid), , Hyperboloid
942.80904 cm3
A parallelopiped.
Trying to figure this out too...
V = 1/3 * base area * height.
If the area of the base of the tetrahedron is A square units and the vertical height is h units, then the volume is V = 1/3*A*h cubic units. If the tetrahedron is regular, with sides of length of length s units, then V = sqrt(2)/12*s3 cubic units.
There are many possible shapes. The most general, which has a specific name is a parallelopiped. A cube is a special case of a parallelopiped.
Assuming you mean a tetrahedron, the volume is 1/3*area of base*height cubic units.