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Volume of a parallelogram = cross-section area times length
The volume(cm3) of a tetrahedron is 1/3 (area of the base)X height
Cubes, Cuboids, Spheres, Ellipsoids. Pyramids, and name suffixed with 'hedron'.e.g. 'Tetrahedron. Parallelopiped, Rhombohedron, Prism, Trapezohedron, Cylinder. 'Lemon'(very special form of ellipsoid), , Hyperboloid
V = 1/3 * base area * height.
Trying to figure this out too...
A cuboid, a pentagonal pyramid, a di-tetrahedron, a parallelopiped are some possibilities.
Volume of a parallelogram = cross-section area times length
The volume(cm3) of a tetrahedron is 1/3 (area of the base)X height
Cubes, Cuboids, Spheres, Ellipsoids. Pyramids, and name suffixed with 'hedron'.e.g. 'Tetrahedron. Parallelopiped, Rhombohedron, Prism, Trapezohedron, Cylinder. 'Lemon'(very special form of ellipsoid), , Hyperboloid
A parallelopiped. A cuboid is a special case of a parallelopiped, and a cube is a special case of a cuboid.
942.80904 cm3
A parallelopiped.
V = 1/3 * base area * height.
Trying to figure this out too...
If the area of the base of the tetrahedron is A square units and the vertical height is h units, then the volume is V = 1/3*A*h cubic units. If the tetrahedron is regular, with sides of length of length s units, then V = sqrt(2)/12*s3 cubic units.
There are many possible shapes. The most general, which has a specific name is a parallelopiped. A cube is a special case of a parallelopiped.
Assuming you mean a tetrahedron, the volume is 1/3*area of base*height cubic units.