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Volume of a parallelogram = cross-section area times length
The volume(cm3) of a tetrahedron is 1/3 (area of the base)X height
V = 1/3 * base area * height.
Trying to figure this out too...
If the area of the base of the tetrahedron is A square units and the vertical height is h units, then the volume is V = 1/3*A*h cubic units. If the tetrahedron is regular, with sides of length of length s units, then V = sqrt(2)/12*s3 cubic units.
A cuboid, a pentagonal pyramid, a di-tetrahedron, a parallelopiped are some possibilities.
Volume of a parallelogram = cross-section area times length
The volume(cm3) of a tetrahedron is 1/3 (area of the base)X height
A parallelopiped. A cuboid is a special case of a parallelopiped, and a cube is a special case of a cuboid.
942.80904 cm3
A parallelopiped.
V = 1/3 * base area * height.
Trying to figure this out too...
If the area of the base of the tetrahedron is A square units and the vertical height is h units, then the volume is V = 1/3*A*h cubic units. If the tetrahedron is regular, with sides of length of length s units, then V = sqrt(2)/12*s3 cubic units.
There are many possible shapes. The most general, which has a specific name is a parallelopiped. A cube is a special case of a parallelopiped.
Assuming you mean a tetrahedron, the volume is 1/3*area of base*height cubic units.
Is called a Dodecagon. * * * * * A dodecagon is a 2-dimensional (plane) shape with 12 SIDES. The term EDGES is normally used in the context of 3-dimensional objects. One such shape is a parallelopiped. A cube is a special case of a parallelopiped. In 3-D, a parallelopiped is to a cube what, in 2-D, a parallelogram is to a square.