3 blocks east
To calculate the total displacement, we can break down the student's movements into net east-west and north-south components. The student walks 3 blocks east, 1 block west (net 2 blocks east), and 2 blocks north, then 2 blocks south (net 0 blocks north). Therefore, the total displacement is 2 blocks east, resulting in a final displacement of 2 blocks east.
To find the displacement, we can use the Pythagorean theorem. The person drives 6 blocks north and 6 blocks west, forming a right triangle with both legs measuring 6 blocks. The displacement is the hypotenuse of this triangle, calculated as √(6² + 6²) = √72, which simplifies to 6√2 blocks. The direction of the displacement is northwest.
Patrice travels a total of 4.0 blocks east, 6.0 blocks north, and 4.0 blocks west. To find the total distance she has traveled, we simply add these distances together: 4.0 + 6.0 + 4.0 = 14.0 blocks. Therefore, Patrice has traveled a total of 14.0 blocks.
The answer is....................................... LOL do it yourself, lml no its ................ Me giving you the answer wont help you............. I bet your still waiting or you went back but okay... your still here -________- suits your self Its 2 blocks east!
If Meg walks 5 blocks south, then turns around and walks 8 blocks back, her displacement is 3 blocks.
3 blocks east
5 blocks
To find the displacement, we can use the Pythagorean theorem. The person drives 6 blocks north and 6 blocks west, forming a right triangle with both legs measuring 6 blocks. The displacement is the hypotenuse of this triangle, calculated as √(6² + 6²) = √72, which simplifies to 6√2 blocks. The direction of the displacement is northwest.
The displacement made by the stranger from the origin to the Mini store is 5 blocks north and 3 blocks east. This can be represented by a vector with a magnitude of 5 blocks and a direction of 37 degrees north of east.
A girl delivering newspapers covers her route by traveling 10.00 blocks west, 4.00 blocks north, and then 2.00 blocks east Opposite = 4 (related to y axis on 4 blocks north) Adjacent = 8 (related to x axis on 10 b west - 2 blocks east) tan -1 x (4/8) tan theta - 26.6 degrees since you are looking for the hypotenuse, then sin theta = opp/hyp sin 26.6=4/hypotenuse 4/sin(26.6) = 8.9 blocks
move 6 blocks west
Edward and his family are sightseeing. They walk two blocks north, four blocks west and two blocks south. All together they have walked blocks and have a total displacement magnitude only of 8. 2+4+2=8
The distance and displacement are the same when the displacement is parallel to itself or straight. Displacement is a vector and distance is a real number or scalar. If an object is displaced around a circle the displacement is zero and the distance is 2pi r.
That is incorrect. The distance travelled north cancels out the distance travelled south. Therefore - he only travels three blocks east.
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.