The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
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What is the correct displacement for the following vectors 4km south 2km north 5km south and 5km north?
2km south
What is the correct displacement for the following vectors 4 km south 2 km north 2 km south and 5 km north?
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
What s the correct displacement for the following vectors 4 km south 2 km north 5 km south and 5 km north?
2 km south.
What is the correct displacement for the following vectors 4 km south 2 km north 5 km south and 5 km north?
The resultant is 2 km South.
What are displacement vectors of 2 km south and 6 km north and 5 km south and 6 km north combine to a total displacement of?
2 km south
What is the correct desplacment of the following vectors 4km south 2km north 5km south 5 km north?
4-2+5-5 = 2 km south. It's simple addition, keeping track of the plus and minus signs (south is plus, north is minus).
How do you find north south east west?
find the resultant of the following displacement a=20km 30south of east
If the displacement is negative 2 north and represents a positive displacement What is the direction?
south
A -2 displacement towards the north represents a positive displacement towards the south?
Indeed it is.
Which one is correct among a hospital and an hospital?
In North America the correct usage is 'a hospital'. 'An' is used only when the following letter is not distinctly pronounced.
How is distance and displacement the same?
Distance is a scalar and is the total amount of distance you traveled, without direction. If you walk 20m North, then walk 18m South, your distance will be 38m altogether. Therefore to calculate the overall distance in a trip with many legs, you add the magnitudes of the length of each leg without worrying about the direction. Displacement is the vector equivalent of distance and is measured from the starting point to the ending point in one straight line, with direction. So if you walk 20m North, then walk 18m South, your displacement will be 2m North. Therefore to calculate the overall displacement in a trip with many legs, you use vector summation to add all the vectors representing each of the legs.
Can the magnitude of the resultant of two vectors be less than the magnitude of any one of the vectors?
Of course. The resultant of +4 north and +4 south is zero.
What is the displacement of a car traveling 10 km north t km east 15 km south and 5 km north?
What is the displacement of a car traveling 10 km north 5km east 15 km south and 5 km north?
What is the displacement of a car if it drives 20miles north and then 3 miles south?
It's 17.0m North. (20N - 3S)
What is difference between displacement and distance?
Displacement is a form of distance but unlike distance it is a vector. It has both measure and direction. If I moved 10 meters east then the distance I moved would be 10 m but my displacement would be 10m East as vectors must have a direction to make sense.The distance you traveled is how far you moved, while displacement is how far from the starting point you end up.For example, you get in your car and drive two miles north, then turn around and drive five miles south. The distance you travelled is 7 miles, but your displacement is three miles because that's how far you are from your starting point.
Is the magnitude of the sum of two vectors always less than the sum of the magnitude of the two vectors?
No, they could be equal If the two vectors are opposites (180 degrees apart) like r and -r, then the sum of their magnitudes is the magnitude of their sum. ?? North 1 plus East 1 gives NorthEast 1.414. North 1 plus South 1 gives 0. North 1 plus North 1 gives North 2, which is equal to, not less than 1+1.
A car is driven 215 km west and then 85 km southwest. What is the displacement of the car from the point of origin magnitude and direction draw a diagram.?
To solve this problem, I must explain the concept of vectors. Vectors merely consist of a magnitude and a direction. For this type of problem, the magnitude is the distance the car travels. Imagine arrows that are pointed in the direction of movement, and the same distance as the car moves. In this case, we will say that north is zero degrees. We know that since the car travels 215 km west, the first displacement is 215 west, and this is easy to visualize exactly where the car is. However, since the 85 km displacement is diagonal, it is more difficult to determine where exactly the vector goes. We must break this into components, in other words, two separate vectors. We must find out how far the car moves in the north-south direction, and how far it moves in an east-west direction. We do this using trigonometry. When we assumed that north is zero degrees, we determine that southwest corresponds to -135 degrees. So the calculations go as follows. For the east-west component, 85cos(-135)=-60.104 km. This means that the displacement from this vector is 60.104 km west. For the north-south component, 85sin(-135)= -60.104 km. This means that the displacement for this vector is 60.104 km south. We then add these two vectors to the 215km west. 215km + 60.104km = 275.104km. This means that the car has traveled a total of 275.104 km west. Since the car didn't travel south initally, we can just say that the car traveled 60.104 km south. To find out the straightline distance that this displacement is from the start, we use the pythagreaon theorem. The west and south displacements make up the legs of a right triangle. By adding the squares of these displacements, then taking the square root of the sum, we get 281.593 km from the start point. To get the angle of this displacement, use the inverse tangent function of the north-south component divided by the east-west component. We get 12.32 degrees. We must add this to the 90 degrees we get from the west component, so in the end, the vector can be defined as 281.593 km, -102.32 degrees. Hope this helps.
Mark walked 2 miles east then 1 mile north. How would you determine his total displacement?
That would be the vector sum; in this case use Pythagorean theorem as east and north are perpendicular; total displacement is sqrt of 5
What are unit vectors used for in real life?
In real life unit vectors are used for directions, e.g east, north and up(zenith). The unit vector specifies the direction. Gyroscopes maintain a direction and keep things level. Whenever and where ever location is important, unit vectors are a part of real life. Whenever directions are important in your real life, then unit vectors are important. If everything was confined to move along a straight line, then unit vectors would not be important. If you can move in a plane, then unit vectors are important. Moving in space, unit vectors are more important. cars, ships and planes all move in space. Controlling and tracking these all involve unit vectors.
Can a position time graph tell in which directionthe displacement of an object is?
Yes. If the slope is positive, the direction of the displacement is positive (e.g. north, east, or right). If the slope is negative, the direction of the displacement is negative (e.g. south, west, or left).
A car pulls out from its garage begins to head north for 10 km then heads east for 5km then heads south for 15km and finally comes to rest after heading north 5 km What is the displacement?
The displacement of the car is 5 km to the east.
Is it possible that a body travels a certain distance but its displacement is zero explain with examples?
Yes it is possible. Any body that travels in any particular closed shape (circle, square, triangle etc.) and returns to the point in which it started would have travelled a certain distance but the sum of its displacement would be nil. Example: A body travels in a 1 mile north, then 1 mile west, then one mile south and finally 1 mile east (ie. a square). The body has travelled a distance of 4 miles. The bodys displacement is 0 miles due to it returning to the point in which it started. You can calculate displacement using vectors. For this example assuming east is positive x and north is positive y: north + west + south + east y -x -y +x = 0
When do we use vector algebra in daily life?
In real life unit vectors are used for directions, e.g east, north and up. The unit vector specifies the direction. Gyroscopes maintain a direction and keep things level. Whenever and where ever location is important, unit vectors are a part of real life. Whenever directions are important in your real life, then unit vectors are important. If everything was confined to move along a straight line, then unit vectors would not be important. If you can move in a plane, then unit vectors are important. Moving in space, unit vectors are more important. cars, ships and planes all move in space. Controlling and tracking these all involve unit vectors.
A girl delivering newspapers covers her route by traveling 3.00 blocks west 4.00 blocks north then 6.00 blocks east what is her displacement?
a) Displacement: 4.00 blocks north + (6.00-3.00)=4.00 blocks north/ 3.00 blocks east= total displacementb) Total Distance: 3.00 + 4.00 + 6.00= 13.00 blocks
Is dakar located south or north of the Equator?
North is correct
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