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Molar mass is a whole number multiple of the a) empirical formula mass c) average atomic mass b) amu d) mass percent?
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Calculate the empirical formula of a compound formed from 3 percent C 0.3 percent H and 96.7 percent you Which formula below correctly represents the empirical formula?
Chi a+
Calculate the empirical formula of a compound formed from 3 percent c 3 percent h and 96 7 percent you which formula below correctly represents the empirical formula?
CHI3
What is the empirical formula for vanillin with 63.15 percent 5.30 percent 31.55 percent percent composition?
C3 h3o
How do you calculate the molecular formula of a substance which contain 80 percent C and 20 percent H?
You can only calculate the empirical formula because you do not have a mass of this compound given. To do the empirical formula assume 100 grams and change percent to grams. Get moles. 80 grams Carbon (1 mole C/12.01 grams) = 6.66 moles C 20 grams hydrogen (1 mole H/1.008 grams) = 19.84 moles H the smallest becomes 1 in the empirical formula and the other number is divided by it, Thus; H/C 19.84 moles H/6.66 moles C = 2.9, which we call 3 so, CH3 --------------- is the empirical formula To get the molecular formula tour question needed to read; How to calculate molecular formula from such ans such mass of compound with these percentages of elements, Which, of course, your question did not provide. Then you would have divided that given mass by the mass total of the elements of the empirical formula, got a whole number by which you would have multiplied the numbers of your empirical formula to get molecular formula.
What is the empirical formula for 5.17 percent 35.9 percent and 58.9 percent?
to get 5.17% of a number, multiply it by 0.0517 to get 35.9% of a number, multiply it by 0.359, and to get 58.9% of a number, multiply it by 0.589
Can you determine the molecular formula of a substance from its percent composition?
Not completely. The empirical formula of a substance can be determined from its percent composition, but a determination of molecular weight is needed to decide which multiple of the empirical formula represents the molecular formula.
Calculate the empirical formula of a compound formed from 3 percent C 0.3 percent H and 96.7 percent you Which formula below correctly represents the empirical formula?
Chi a+
Calculate the empirical formula of a compound formed from 3 percent c 3 percent h and 96 7 percent you which formula below correctly represents the empirical formula?
CHI3
Empirical formula of a compound containing 60.3 percent magnesium and 39.7 percent oxygen?
The empirical formula of this compound would be MgO.
Nicotin contains 74.03 percent C 8.70 percent H and 17.27 percent N by mss The mass of nicotine is 162.23gmol What is the empirical formula and molecular formula for nicotine?
The empirical formula of nicotine is C7H10N2, calculated by converting the percentages into moles and finding the simplest whole-number ratio. To find the molecular formula, divide the molar mass of nicotine by the empirical formula mass to get the multiple, which is 2. Therefore, the molecular formula of nicotine is C14H20N4.
What is the empirical formula for a molecule containing 46.8 percent si and 53.2 percent o?
The empirical formula for a molecule containing 46.8 percent si and 53.2 percent o is in the middle of the two. These added together and divided by two will net the average result.
Explain why the percent composition of certain compounds are not sufficient to determine the compounds molecular formulas?
The percent composition only tells us the relative proportions of the elements present in the compound, not the specific arrangement of atoms within the molecule. Different compounds can have the same percent composition but different structures, leading to different molecular formulas. For example, both ethanol (C2H6O) and dimethyl ether (C2H6O) have the same percent composition, but are different compounds with distinct structures.
What is the percent composition of a compound with the empirical formula CO2?
The percent composition of a compound with the empirical formula CO2 is 27.3% carbon and 72.7% oxygen.
What is the empirical formula for a compound that is 43.6 percent phosphorus and 56.4 percent oxygen?
p2o5
75.7 percent arsenic and 24.3 percent oxygen what empirical formula would it have?
As2O3
What would the empirical formula be for 66 percent Barium and 34 percent Chlorine?
BaCl2
What is the empirical formula for 13 percent magnesium and 87 percent bromine?
The empirical formula for a compound containing 13% magnesium and 87% bromine is MgBr2. This is because the ratio of magnesium to bromine atoms in the compound is 1:2, which corresponds to the formula MgBr2.
