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What is the difference between a parallegram and a rhombus?
well a parallelogram is like parallel lines when theynever meet up together just like a rhombus. A rhombus is just a square but they say it got hit by a bus, it also has obtuse angles.
Which angle hits a mirror or glass block?
The angle does not hit anything! A ray of light hits a mirror or glass block and the angle that the ray makes with the vertical at the point of contact is the angle of incidence.
When a figure can be folded on a line so that its two parts are congruent?
symmetry? lines of symmetry? something of the sort, i believe..why am i answering this? someone hit me
What are the four relationships that 2 lines in a space can have?
The four relationships two lines in space can have are perpendicular, parallel, skew, and intersecting. perpendicular refers to when lines are crossing each other making four ninety degree angles. Parallel lines have the same slope and therefore remain the same distance from each other forever; they never touch. Intersecting lines cross without making ninety degree angles. Skew line are lines that do not intersect and are also not parallel. Its like a bridge. cars drive across it and do not hit the cars below although from a aerial view they are in the same place. Because of this phenomenon skew lines cannot exist in a two dimensional situation. Skew lines can only be present in 3 or more dimensional situations.
If a ball rolls off the edge of a table two meters above the floor and with an initial velocity of 20 meters per second what is the ball's acceleration and velocity just before it hits the ground?
The horizontal velocity has no bearing on the time it takes for the ball to fall to the floor and, ignoring the effects of air resistance, will not change throughout the ball's fall, so you know Vx. The vertical velocity right before impact is easily calculated using the standard formula: d - d0 = V0t + [1/2]at2. For this problem, let's assume the floor represents zero height, so the initial height, d0, is 2. Further, substitute -g for a and assume an initial vertical velocity of zero, which changes our equation to 0 - 2 = 0t - [1/2]gt2. Now, solve for t. That gives you the time it takes for the ball to hit the floor. If you divide the distance traveled by that time, you know the average vertical velocity of the ball. Double that, and you have the final vertical velocity! (Do you know why?) Now do the vector addition of the vertical velocity and the horizontal velocity. Remember, the vertical velocity is negative!
