LCM of 1 - 6 is 60 so 61 would leave a remainder of 1, but doesn't divide by 11.
Try other multiples of 60 and add 1: 120 + 1 = 121 which is an exact multiple of 11,
and there you have it!
2521
2521
forty-one
It is LCM(5, 8) + 1 = 41.
HCF(5, 8) + 1 = 40 + 1 = 41
2521
31
2521
41
41
forty-one
2 or 62 no because 5 is not divisible in 2 or 62.
It is LCM(5, 8) + 1 = 41.
HCF(5, 8) + 1 = 40 + 1 = 41
41
Please help me my homework has this question and Im like OMG im in trouble if I dont do this!
6. 6 % 5 = 1, where % is the modulo operator (a fancy way of saying that it finds the remainder). If you were instead dividing by 8 and not 5, then the answer would be 9.