-3, -5, -7, -9, -11
-6, -4, -2, 0, 2 or -6, -8, -10, -12, -14
-6, -4, -2, 0, 2 -6, -8, -10, -12, -14
Let the five consecutive integers be ( x-2, x-1, x, x+1, x+2 ). The sum of these integers can be expressed as ( (x-2) + (x-1) + x + (x+1) + (x+2) = 5x ). To find the integers that sum to 0, we set ( 5x = 0 ) which gives ( x = 0 ). Thus, the five consecutive integers are -2, -1, 0, 1, and 2.
The integers are 10 and 11.
50
-6, -5, -4, -3 and -2.
-3, -1, 1, 3, 5
4,6,8,9,10
-6, -4, -2, 0, 2 or -6, -8, -10, -12, -14
-6, -4, -2, 0, 2 -6, -8, -10, -12, -14
The integers are 10 and 11.
50
The value of the greatest integer is 76. This occurs when the set of five consecutive integers is all even numbers.
5872345098234783904672083946728390752430689723409687298290843 theres your answer
The integers would begin with 10.
The numbers are -2, -1, 0, 1 and 2.
Well, well, well, look who's trying to do some math! If the sum of ten consecutive integers is five, then the middle number is 0. So, the largest integer would be 4. Keep crunching those numbers, honey!