The integers would begin with 10.
They are 14, 16 and 18.
The let statement is: let the smallest of the three integers be x.
-1, 1 and 3
The product of two consecutive positive integers can be found by multiplying the smaller integer by the larger integer. If the smaller integer is represented as ( n ), then the larger integer would be ( n + 1 ). Therefore, the product of two consecutive positive integers is ( n \times (n + 1) ).
5*x = 4*(x+2) + 3 so 5x = 4x + 8 + 3 = 4x + 11 Subtracting 4x from both sides: x = 11 So the two integers are 11 and 13.
The sum of three consecutive integers is -72
They are 14, 16 and 18.
10-11-12
The numbers are 14, 16 and 18.
The let statement is: let the smallest of the three integers be x.
The integers are 5 and 7.
9,11,13
-1, 1 and 3
The product of two consecutive positive integers can be found by multiplying the smaller integer by the larger integer. If the smaller integer is represented as ( n ), then the larger integer would be ( n + 1 ). Therefore, the product of two consecutive positive integers is ( n \times (n + 1) ).
5*x = 4*(x+2) + 3 so 5x = 4x + 8 + 3 = 4x + 11 Subtracting 4x from both sides: x = 11 So the two integers are 11 and 13.
One possible answer is -4 and -3.
There can be no such integers: a smaller integer cannot be 5 times the larger number.