(9,-2)
13
x^2 - 15x + 56 = 0
I assume you mean (8, 0). If one or both of the coordinates are zero, the point is not in any of the four quadrants. Instead, it is on the axes - between two quadrants.
To determine which ordered pair could be a solution to the inequality (4y - 3x - 2 > 0), you can substitute the values of the ordered pair into the inequality. For example, if we take the ordered pair (1, 2), substituting gives (4(2) - 3(1) - 2 = 8 - 3 - 2 = 3), which is greater than 0, thus (1, 2) is a solution. You can test other pairs similarly to find more solutions.
There are infinitely many ordered pairs that satisfy this equation. Supply any value for x, then solve for y to get the other part of the pair.
13
8
1/8
x^2 - 15x + 56 = 0
I assume you mean (8, 0). If one or both of the coordinates are zero, the point is not in any of the four quadrants. Instead, it is on the axes - between two quadrants.
It is 2.
To determine which ordered pair could be a solution to the inequality (4y - 3x - 2 > 0), you can substitute the values of the ordered pair into the inequality. For example, if we take the ordered pair (1, 2), substituting gives (4(2) - 3(1) - 2 = 8 - 3 - 2 = 3), which is greater than 0, thus (1, 2) is a solution. You can test other pairs similarly to find more solutions.
There are infinitely many ordered pairs that satisfy this equation. Supply any value for x, then solve for y to get the other part of the pair.
The ordered pair to complete is not included... To complete the ordered pair, take the given number, let's say it is (?, 3): x = ?, y = 3 Start by substituting it in for y, and solve for x y = 4 - 5x (rearranged to slope-intercept form for simplicity) 3 = 4 - 5x -1 = -5x x = 1/5 = .2 The completed pair is now: (.2, 3) For another example, let's take the given number as (8, ?), x = 8, y = ? y = 4 - 5x y = 4 - 5 x 8 y = 4 - 40 y = -36 (8, -36)
y=(-1) x=(2)
x = 2y - 23x - y = 143(2y - 2) - y = 146y - 6 - y = 145y - 6 = 145y = 20y = 4x = 2(4) - 2x = 8 - 2x = 6The ordered pair is (6,4).
Without an equality sign the given terms can't be considered to be a straight line equation.