(9,-2)
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x^2 - 15x + 56 = 0
I assume you mean (8, 0). If one or both of the coordinates are zero, the point is not in any of the four quadrants. Instead, it is on the axes - between two quadrants.
There are infinitely many ordered pairs that satisfy this equation. Supply any value for x, then solve for y to get the other part of the pair.
Without any equality sign and not knowing whether or not 2 is + or they cannot be classed as equations