Yes, it could. "Poly" means "many" as in "poly technic" which means "many - areas of learning". "nomial" means something like "named parts".
If you factorise the simple expression: (x + 2)(x - 3) and you multiply it out you get
x squared - x - 6. This is a polynomial with just 2 terms that mention x, and the independent term -6.
2x squared + 4x cubed + 7x + x to the power 4 minus 3.6 is a polynomial with x mentioned in 4 of the terms plus the independent number 3.6
-2 and -6
Not quite. The polynomial's linear factors are related - not equal to - the places where the graph meets the x-axis. For example, the polynomial x2 - 5x + 6, in factored form, is (x - 2) (x - 3). In this case, +2 and +3 are "zeroes" of the polynomial, i.e., the graph crosses the x-axis. That is, in an x-y graph, y = 0.
(x+7) and (x-3)
(x+8)(x-3)
2 and 7.
It is useful to know the linear factors of a polynomial because they give you the zeros of the polynomial. If (x-c) is one of the linear factors of a polynomial, then p(c)=0. Here the notation p(x) is used to denoted a polynomial function at p(c) means the value of that function when evaluated at c. Conversely, if d is a zero of the polynomial, then (x-d) is a factor.
2 or 5
false
4 and 5 -4 and -8
-2 and -6
Not quite. The polynomial's linear factors are related - not equal to - the places where the graph meets the x-axis. For example, the polynomial x2 - 5x + 6, in factored form, is (x - 2) (x - 3). In this case, +2 and +3 are "zeroes" of the polynomial, i.e., the graph crosses the x-axis. That is, in an x-y graph, y = 0.
If p, q, r, ... are the roots of the equations, then (x-p), (x-q), (x-r), etc are the factors (and conversely).
B
a
a
The values that make each of the factors zero. In other words, you need to solve:x - 2 = 0 and: x - 5 = 0
(x+7) and (x-3)