Yes (in a Euclidean plane)..
It's the theorem that says " One and only one perpendicular can be drawn from a point to a line. "
Only one line can be drawn perpendicular to a given line at a specific point on that line in a plane. This is based on the definition of perpendicular lines, which intersect at a right angle (90 degrees). The uniqueness of this perpendicular line arises from the geometric properties of Euclidean space.
There is exactly one line that can be drawn perpendicular to a given line at a specific point on that line in three-dimensional space. This is because a perpendicular line will intersect the original line at a right angle, and in three-dimensional geometry, any point on a line can have only one such unique perpendicular direction.
True
3y + x = k where k is some constant which can only be determined if a point on it is known. There is no such point given.
It's the theorem that says " One and only one perpendicular can be drawn from a point to a line. "
Only one line can be drawn perpendicular to a given line at a specific point on that line in a plane. This is based on the definition of perpendicular lines, which intersect at a right angle (90 degrees). The uniqueness of this perpendicular line arises from the geometric properties of Euclidean space.
There is exactly one line that can be drawn perpendicular to a given line at a specific point on that line in three-dimensional space. This is because a perpendicular line will intersect the original line at a right angle, and in three-dimensional geometry, any point on a line can have only one such unique perpendicular direction.
Only one
only 1
In a Euclidean plane, only one.
Two points determine a line. Also there is one and only line perpendicular to given line through a given point on the line,. and There is one and only line parallel to given line through a given point not on the line.
Biconditional Statement for: Perpendicular Bisector Theorem: A point is equidistant if and only if the point is on the perpendicular bisector of a segment. Converse of the Perpendicular Bisector Theorem: A point is on the perpendicular bisector of the segment if and only if the point is equidistant from the endpoints of a segment.
True
3y + x = k where k is some constant which can only be determined if a point on it is known. There is no such point given.
Yes, but only in principle. In practice, you won't live long enough. Putting it in more positive terms: No matter how many lines have already been drawn perpendicular to a given line [segment], there's always enough room for a lot more of them.
Perpendicular lines will only share one point: the point of intersection, where the two lines meet.