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program kvadratine;
var a,b,c:integer;
D: real;
begin
writeln('iveskite kvadratines lygties Ax^2+Bx+C=0 koeficientus A B C');
readln(a,b,c);
D:=b*b - 4*a*c;
if D<0 then
writeln('Nera sprendiniu')
else if D=0 then
writeln('D=0, taigi:', 'x1 = ',(-b)/2*a:0:2)
else
writeln('D>0, taigi: ','x1=',(-b+sqrt(D))/2*a:0:2,' x2=',(-b*sqrt(D))/2*a:0:2);
end.
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What is the difference between a radical equation and a quadratic equation?
radical equations have sq roots, cube roots etc. Quadratic equations have x2.
What are quadratic equations with real roots?
If the discriminant of the quadratic equation is zero then it will have 2 equal roots. If the discriminant of the quadratic equation is greater than zero then it will have 2 different roots. If the discriminant of the quadratic equation is less than zero then it will have no roots.
Is it possible for two different quadratic equations to have the same roots?
yes
Can all quadratic equations be solved?
Well, that depends on what you mean "solve by factoring." For any quadratic equation, it is possible to factor the quadratic, and then the roots can be recovered from the factors. So in the very weak sense that every quadratic can be solved by a method that involves getting the factors and recovering the roots from them, all quadratic equations can be solved by factoring. However, in most cases, the only way of factoring the quadratic in the first place is to first find out what its roots are, and then use the roots to factor the quadratic (any quadratic polynomial can be factored as k(x - r)(x - s), where k is the leading coefficient of the polynomial and r and s are its two roots), in which case trying to recover the roots from the factors is redundant (since you had to know what the roots were to get the factors in the first place). So to really count as solving by factoring, it makes sense to require that the solution method obtains the factors by means that _don't_ require already knowing the roots of the polynomial. And in this sense, most quadratic equations are not solvable through factoring.
What are the roots of a quadratic?
The roots of a quadratic function are where the lies interescts with the x-axis. There can be as little as zero.
What is the graph of a quadratic formula?
In general, quadratic equations have graphs that are parabolas. The quadratic formula tells us how to find the roots of a quadratic equations. If those roots are real, they are the x intercepts of the parabola.
What is the difference between a radical equation and a quadratic equation?
radical equations have sq roots, cube roots etc. Quadratic equations have x2.
Why do you use square roots to solve quadratic equations?
Because it's part of the quadratic equation formula in finding the roots of a quadratic equation.
What are quadratic equations with real roots?
If the discriminant of the quadratic equation is zero then it will have 2 equal roots. If the discriminant of the quadratic equation is greater than zero then it will have 2 different roots. If the discriminant of the quadratic equation is less than zero then it will have no roots.
What form is the solving for the roots of quadratic equations?
Using the quadratic equation formula or completing the square
What are the 4 quadratic equations?
actoring, using the square roots, completing the square and the quadratic formula.
What is the flow chart to find the roots of quadratic equations?
ax+b=)
Is it possible for two different quadratic equations to have the same roots?
yes
Can all quadratic equations be solved?
Well, that depends on what you mean "solve by factoring." For any quadratic equation, it is possible to factor the quadratic, and then the roots can be recovered from the factors. So in the very weak sense that every quadratic can be solved by a method that involves getting the factors and recovering the roots from them, all quadratic equations can be solved by factoring. However, in most cases, the only way of factoring the quadratic in the first place is to first find out what its roots are, and then use the roots to factor the quadratic (any quadratic polynomial can be factored as k(x - r)(x - s), where k is the leading coefficient of the polynomial and r and s are its two roots), in which case trying to recover the roots from the factors is redundant (since you had to know what the roots were to get the factors in the first place). So to really count as solving by factoring, it makes sense to require that the solution method obtains the factors by means that _don't_ require already knowing the roots of the polynomial. And in this sense, most quadratic equations are not solvable through factoring.
How do you write quadratic equations using roots?
If the two roots are x = r1 and x = r2 then the quadratic equation is: (x - r1)(x - r2) = x2 - (r1 + r2)x + r1r2 = 0
What are the symbols used in quadratic equations?
Addition, subtraction signs, brackets, squares and powers, square roots and roots, fractions. Random variables are also used, like x.
What is Factor-Factorproduct relationship?
The Factor-Factor Product Relationship is a concept in algebra that relates the factors of a quadratic equation to the roots or solutions of the equation. It states that if a quadratic equation can be factored into the form (x - a)(x - b), then the roots of the equation are the values of 'a' and 'b'. This relationship is crucial in solving quadratic equations and understanding the behavior of their roots.
