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Let the length be 2x+8 and the width be x:

2(2x+8+x) = 64

4x+16+2x = 64

6x = 64-16

6x = 48

x = 8

Therefore: length = 24m and width = 8m

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Q: Perimeter of a rectangle is 64m length is 8m more than twice the width what is the dimensions?
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