The line perpendicular to a line with a slope of 1/5 has a slope of -5.
-5/3 it is always the opposite reciprocal for a perpendicular slope
If you mean: y = 4x+5 then the perpendicular slope is -1/4
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If the gradient of a line is m, the gradient of a line perpendicular to it (m') is such that mm' = -1, that is: m' = -1/m So for: y = -x - 5 m = -1, so the gradient of a perpendicular line is: m' = -1/-1 = 1 So a general line perpendicular to y = -x - 5 would be: y = x + c A specific line perpendicular to y = -x - 5 at point (xo, -xo-5) on the line is: y - (-xo-5) = 1(x - xo) ⇒ y = x - 2xo - 5
The line perpendicular to a line with a slope of 1/5 has a slope of -5.
-5/3 it is always the opposite reciprocal for a perpendicular slope
If you mean y = 2x+5 then the perpendicular slope is -1/2
If you mean: y = 4x+5 then the perpendicular slope is -1/4
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If the gradient of a line is m, the gradient of a line perpendicular to it (m') is such that mm' = -1, that is: m' = -1/m So for: y = -x - 5 m = -1, so the gradient of a perpendicular line is: m' = -1/-1 = 1 So a general line perpendicular to y = -x - 5 would be: y = x + c A specific line perpendicular to y = -x - 5 at point (xo, -xo-5) on the line is: y - (-xo-5) = 1(x - xo) ⇒ y = x - 2xo - 5
The line "x = 6" will be perpendicular to any line "y = C", where C is any constant. That means that the line which is perpendicular to "x=6" and passes through [-4, 5] will be "y = 5"
If two nonvertical lines are perpendicular, then the product of their slope is -1.An equivalent way of stating this relationship is to say that one line is perpendicular to another line if its slope is the negative reciprocal of the slope of the other. For example, if a line has slope 3, any line having slope - 1/3 is perpendicular to it. Similarly, if a line has slope - 4/5, any line having the slope 5/4 is perpendicular to it.
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Points: (5, -1) and (2, -5) Slope: 4/3 Perpendicular slope: -3/4
The slope of the perpendicular to the line passing through P1(3,6) and P2(5,1) is 2/5. Note: the slope of the original line is (change in y)/(change in x), yielding -5/2. The slope of the perpendicular is the negative reciprocal, 2/5
-1/5