The question cannot be answered as stated since the maximum value possible is 1+2+3+4+5+6+7+8+9 = 45.
There must be implicit multiplication by 10 so that adjacent digits are combined into a 2-digit number.
Any number between a googol/10 and a googol minus 1.
There are a total of 900 3-digt numbers (100 thru 999); Of these there are 9x9x8 = 648 numbers that do not contain repeating digits (first position: 9 possibilities, second place 9 possibilities; the 10 digits minus the one used in the first place. and third place 8 possibilities; 10 digits minus the two used in the first and second places) So, there should be 900-648=252 3-digit numbers with at least one repeating digit.
It is easiest to explain with an example. Suppose you have a number 4627. Then the number obtained by reversing [the order of] its digits is 7264. The difference between them is the bigger number minus the smaller number. So here it would be 7264 - 4627 = 2637.
1000000 minus 447618 equals 552382. This subtraction can be calculated by lining up the digits in the two numbers, starting from the rightmost column (ones place) and subtracting each corresponding pair of digits. If necessary, borrowing may be required when the digit being subtracted is larger than the digit it is being subtracted from.
It is not necessarily the biggest number because it could be a minus something
Any number between a googol/10 and a googol minus 1.
It is: 97 minus 11 = 86
You need to put a minus plus sign before any set of numbers that sums to 23, and a minus sign before all other digits. So + before 6, 8 and 9.
It is: 200,000 minus 200 = 199,800
200,000 minus 200 = 199,800
There are a total of 900 3-digt numbers (100 thru 999); Of these there are 9x9x8 = 648 numbers that do not contain repeating digits (first position: 9 possibilities, second place 9 possibilities; the 10 digits minus the one used in the first place. and third place 8 possibilities; 10 digits minus the two used in the first and second places) So, there should be 900-648=252 3-digit numbers with at least one repeating digit.
What is the difference between the place value of the 2s in 8 234 260
The sum of the digits in odd position minus the sum of the digits in even position is divisible by 11.
It is easiest to explain with an example. Suppose you have a number 4627. Then the number obtained by reversing [the order of] its digits is 7264. The difference between them is the bigger number minus the smaller number. So here it would be 7264 - 4627 = 2637.
In subtraction, the minuend minus the subtrahend equals the difference.
It is: 3.4 minus 38.736 = -35.336
1000000 minus 447618 equals 552382. This subtraction can be calculated by lining up the digits in the two numbers, starting from the rightmost column (ones place) and subtracting each corresponding pair of digits. If necessary, borrowing may be required when the digit being subtracted is larger than the digit it is being subtracted from.