Since ( PQ ) is parallel to ( RS ), we can use the properties of similar triangles to find the length of ( SQ ). The segments ( RP ), ( PT ), and ( QT ) are proportional. The total length ( RT ) is ( RP + PT = 6 , \text{cm} + 18 , \text{cm} = 24 , \text{cm} ). Using the proportionality, we have:
[ \frac{SQ}{QT} = \frac{RP}{RT} \Rightarrow SQ = QT \cdot \frac{RP}{RT} = 21 \cdot \frac{6}{24} = 5.25 , \text{cm. }]
Thus, the length of ( SQ ) is ( 5.25 , \text{cm} ).
In triangle ABC, let P and Q be the midpoints of sides AB and AC, respectively. By the Midpoint Theorem, the line segment connecting the midpoints of two sides of a triangle is parallel to the third side and half its length. Therefore, since PQ connects the midpoints P and Q, it follows that PQ is parallel to side BC of triangle ABC. This establishes that PQ is parallel to BC, as required.
|PQ|
In the scenario described, angles 1 and 3 are corresponding angles formed by the transversal t intersecting the parallel lines PQ and RS, making them equal in measure. Similarly, angles 2 and 4 are alternate interior angles, which are also equal. Therefore, the relationships between these angles demonstrate the properties of parallel lines and transversals, confirming that angles 1 = angle 3 and angle 2 = angle 4.
The whole sequence (pq) = pb + 8. b is the midpoint so pb = 1/2pq, making pb = 8 and bq also 8 cm
2 + pq
In triangle ABC, let P and Q be the midpoints of sides AB and AC, respectively. By the Midpoint Theorem, the line segment connecting the midpoints of two sides of a triangle is parallel to the third side and half its length. Therefore, since PQ connects the midpoints P and Q, it follows that PQ is parallel to side BC of triangle ABC. This establishes that PQ is parallel to BC, as required.
|PQ|
10 cm
pq
Because b is the mid point of pq, pb = qb. pb is half as long as pq Eq#1....pb = 1/2 pq Eq#2....pq = pb +8 Substitute Eq#1 into Eq #2 pq = 1/2 pq + 8 subtracting1/2 pq from both sides 1/2 pq = 8 pq = 16 problem here: you can't subtract 1/2 ... you would have to divide.
A triangle has 3 line segments
In the scenario described, angles 1 and 3 are corresponding angles formed by the transversal t intersecting the parallel lines PQ and RS, making them equal in measure. Similarly, angles 2 and 4 are alternate interior angles, which are also equal. Therefore, the relationships between these angles demonstrate the properties of parallel lines and transversals, confirming that angles 1 = angle 3 and angle 2 = angle 4.
Line DE is 15 Line PQ is 5 Line DF is 21 Line PR is x 15/3 = 5 21/3 = 7 Line PR is 7 CHECK TO MAKE SURE IT MATCHES (stay safe)
Hacking is against the rules, and can end up with u being banned ~SUGGESTION~ training areas from 1-70 (the fastest way possible) 1-10 snails 10-15 slimes 15-20 green mushroom 21-31 KERNING PQ!!!! 31-35 rats in Ludi 35-51 LUDI PQ 51-70 Orbis PQ, or Carnival PQ, or Ludi Maze PQ
The whole sequence (pq) = pb + 8. b is the midpoint so pb = 1/2pq, making pb = 8 and bq also 8 cm
Province de Quebec
2 + pq