10 cm
B
D
The length of the swimming pool is 20 feet Check: 20 times 10 = 200 square feet
minimum width is like 10 cm and length is like 20 cm
If the fence is parallel and extends 10m from each end of the length of the pool, add 20m to the length of the pool to find the length of the fence; find the width of the fence in the same manner. Hence, 50 + 20 = 70m (length of fence); 25 + 20 = 45m (width of fence). 2(L + W) = Perimeter, so 2 x 115m = 230m perimeter
12. You can figure this out because 20% of 100= 1/5. You then take 1/5 of 10 and get 2. Finally, you add 2 to 10 and get 12.
By Ratio and Proportion: 20% : 8 = 25% : N N = (8 x 25%) ÷ 20% N = 10 Answer: If 20% = 8 then 25% = 10.
if (length>=10 && length<=20) { // length is between 10 and 20, inclusive... }
length ≥ 10 m and length ≤ 20 m
breadth = 4x - 10 ie length + breadth = 5x - 10. Perimeter is double this figure ie 10x - 20 or 10(x - 2)
Area = 10*20 = 200 square units
Three resistors in parallel: 20 ohms, 20 ohms, 10 ohms.1/ total resistance = (1/10) + (1/20) + (1/20) = (2/20) + (1/20) + (1/20) = 4/20 = 1/5 mho.Total resistance = 5 ohms
Constructing the figure, we find the other diagonal to have length 10.The area of the rhombus would thus be 10x8x0.5=40
The length is 20 units and the width is 10 units
36 tiles. First you have to convert 20 inches to feet. There are 12 inches in a foot so 20/12 means you have one and two-thirds length tiles. Then, you have to figure out the lenght of the sides of the room which is the square root of 100 sq ft. which is 10 feet long. Now, you have to figure out how many tiles it will take to do one length of the room by 10/one and two-thirds which is 6 tiles. Finally you have to multiply the length times the width to get how many tiles it takes to fill the room by 6*6=36 tiles
If the "length" of this triangle is the distance from the base to the vertex of the two other sides, it is 100 units^2. (1/2*10*20) if the 'length' is not the aforementioned distance, you do not have enough information.
If you're talking about a rectangle, then the answer is 100. There are 2 sides that have 40 as the length, and double that length is 80. There are 2 sides that have 10 as the width, and double that width is 20. 80 + 20 = 100.
If P = 40 then L + W = 20. The only combination which gives A = 100 is where L and W are both 10, ie the figure is a square of side 10 cm.
-- If the 20 ohms and the nother 10 ohms are configured in series, then the totalnet effective resistance is 30 ohms.-- If they are configured in parallel, then the total effective resistance is 62/3 ohms.