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How do you prove that if a real sequence is bounded and monotone it converges?
We prove that if an increasing sequence {an} is bounded above, then it is convergent and the limit is the sup {an }Now we use the least upper bound property of real numbers to say that sup {an } exists and we call it something, say S. We can say this because sup {an } is not empty and by our assumption is it bounded above so it has a LUB.Now for all natural numbers N we look at aN such that for all E, or epsilon greater than 0, we have aN > S-epsilon. This must be true, because if it were not the that number would be an upper bound which contradicts that S is the least upper bound.Now since {an} is increasing for all n greater than N we have |S-an|
Are bounded domain functions periodic?
No. You can always "cheat" to prove this by simply giving the function's domain a bound.Ex: f: [0,1] --> RI simply defined the function to have a bounded domain from 0 to 1 mapping to the codomain of the set of real numbers. The function itself can be almost anything, periodic or not.Another way to "cheat" is to simply recognize that all functions having a domain of R are bounded functions, by definition, in the complex plane, C.(Technically, you would say a non-compact Hermitian symmetric space has a bounded domain in a complex vector space.) Obviously, those functions include non-periodic functions as well.
Prove that no matter what the real numbers a and b are the sequence with nth term a nb is always an AP?
By "the nth term" of a sequence we mean an expression that will allow us to calculate the term that is in the nth position of the sequence. For example consider the sequence 2, 4, 6, 8, 10,... The pattern is easy to see. # The first term is two. # The second term is two times two. # The third term is two times three. # The fourth term is two times four. # The tenth term is two times ten. # the nineteenth term is two times nineteen. # The nth term is two times n. In this sequence the nth term is 2n.
If EBEC and ABDC prove?
if EB=EC and AB=DC prove <A=<D
How to prove an isosceles triangle with one angle bisector?
What have we got to prove? Whether we have to prove a triangle as an Isoseles triangle or prove a property of an isoseles triangle. Hey, do u go to ALHS, i had that same problem on my test today. Greenehornet15@yahoo.com
How do you prove that if a real sequence is bounded and monotone it converges?
We prove that if an increasing sequence {an} is bounded above, then it is convergent and the limit is the sup {an }Now we use the least upper bound property of real numbers to say that sup {an } exists and we call it something, say S. We can say this because sup {an } is not empty and by our assumption is it bounded above so it has a LUB.Now for all natural numbers N we look at aN such that for all E, or epsilon greater than 0, we have aN > S-epsilon. This must be true, because if it were not the that number would be an upper bound which contradicts that S is the least upper bound.Now since {an} is increasing for all n greater than N we have |S-an|
Is compact metric space is complete?
A compact metric space is not necessarily complete. Compactness only guarantees that every sequence in the space has a convergent subsequence, while completeness requires that every Cauchy sequence converges to a point in the space.
Prove that the sequence n does not converge?
If the sequence (n) converges to a limit L then, by definition, for any eps>0 there exists a number N such |n-L|N. However if eps=0.5 then whatever value of N we chose we find that whenever n>max{N,L}+1, |n-L|=n-L>1>eps. Proving the first statement false by contradiction.
How do you prove that the sum of a convergent sequence divided by n will converge?
You can use the comparison test. Since the convergent sequence divided by n is less that the convergent sequence, it must converge.
Why must every proposition in an argument be tested using a logical sequence?
A logical sequence in an argument is a way to prove a step has a logical consequence. Every proposition in an argument must be tested in this fashion to prove that every action has a reaction.
Given an arbitrary sequence of digits how can you prove it appears somewhere in pi?
It has not yet been proven whether any arbitrary sequence of digits appears somewhere in the decimal expansion of pi.
Prove that every convergent sequence is a Cauchy sequence?
The limits on an as n goes to infinity is aThen for some epsilon greater than 0, chose N such that for n>Nwe have |an-a| < epsilon.Now if m and n are > N we have |an-am|=|(am -a)-(an -a)|< or= |am -an | which is < or equal to 2 epsilor so the sequence is Cauchy.
Are bounded domain functions periodic?
No. You can always "cheat" to prove this by simply giving the function's domain a bound.Ex: f: [0,1] --> RI simply defined the function to have a bounded domain from 0 to 1 mapping to the codomain of the set of real numbers. The function itself can be almost anything, periodic or not.Another way to "cheat" is to simply recognize that all functions having a domain of R are bounded functions, by definition, in the complex plane, C.(Technically, you would say a non-compact Hermitian symmetric space has a bounded domain in a complex vector space.) Obviously, those functions include non-periodic functions as well.
Do the theorems for junior certificate maths have to be exactly right or do they just have to make sense?
There is more than one way to prove a given mathematical proposition. If the sequence of reasoning is valid, then the proof is correct. That is all that is required.
Prove that no matter what the real numbers a and b are the sequence with nth term a nb is always an AP?
By "the nth term" of a sequence we mean an expression that will allow us to calculate the term that is in the nth position of the sequence. For example consider the sequence 2, 4, 6, 8, 10,... The pattern is easy to see. # The first term is two. # The second term is two times two. # The third term is two times three. # The fourth term is two times four. # The tenth term is two times ten. # the nineteenth term is two times nineteen. # The nth term is two times n. In this sequence the nth term is 2n.
What additional evidence would help prove the theory of continental drift?
Look up Alfred Wengener, he was the first to descover this!!!!!!!!!!!!!!To prove the idea of Alfred L. Wegener HERE:Wegener used to fit of the continents, the distribution of fossils, the similar sequence of rocks at numerous locations, ancient climates, and the movement of the polar regions.I'm sure with my answer! obejerojamjam@yahoo.com :))
What does it mean to prove that two figures are congruent using rigid motions?
Proving that two figures are congruent using rigid motions involves demonstrating that one figure can be transformed into the other through a series of translations, rotations, and reflections without changing the size or shape of the original figure. This proof relies on the principle that rigid motions preserve distance and angle measures. By showing that the corresponding parts of the two figures align perfectly after applying these transformations, it can be concluded that the figures are congruent.
