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Prove that no matter what the real numbers a and b are the sequence with nth term a nb is always an AP?
Wiki User
∙ 16y ago
By "the nth term" of a sequence we mean an expression that will allow us to calculate the term that is in the nth position of the sequence. For example consider the sequence 2, 4, 6, 8, 10,... The pattern is easy to see. # The first term is two. # The second term is two times two. # The third term is two times three. # The fourth term is two times four. # The tenth term is two times ten. # the nineteenth term is two times nineteen. # The nth term is two times n.
In this sequence the nth term is 2n.
Wiki User
∙ 16y ago
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