If ( y^3 ) is a palindrome, it means that reading ( y^3 ) from left to right is the same as reading it from right to left. Since ( y^3 ) is formed by concatenating three copies of ( y ), the symmetry in ( y^3 ) implies that ( y ) must itself maintain that symmetry. If ( y ) were not a palindrome, then the concatenation in ( y^3 ) would disrupt the palindromic structure, leading to ( y^3 ) not being a palindrome. Therefore, if ( y^3 ) is a palindrome, ( y ) must also be a palindrome.
72
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
Y3
I understand this to be y3. Then the derivative is 3y2. If y is considered a so-called 'implicit function' of x then the derivative might be written 3y2 dy/dx.
30
y times y times y (or y3)
72
The GCF of y3, y7, y8 is y3
y times y times y
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
y3 x y3 - y (3)3 x 3(3) - 3 9 x 9 - 3 = ? 9 x 9= 81 81 - 3 = 78 I hope that solves your problem
y5 * y3 * y = y5 * y3 * y1 = y5+3+1 = y9
y(y - 2)(y + 2)
Y3
x6 - y6 = (x3)2 - (y3)2 = (x3 + y3) (x3 - y3) = (x + y)(x2 - xy + y2)(x - y)(x2 + xy + y2)
I understand this to be y3. Then the derivative is 3y2. If y is considered a so-called 'implicit function' of x then the derivative might be written 3y2 dy/dx.
30