V=nRT/P
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∙ 14y agop v = n r t v = n r t / p
v = -6
v is -15... -15*2 = -30... -30+11= -19.
H= v over pie r to the second
-7
P V = n R TDivide each side by ( n T ):(P V) / (n T) = R
p v = n r t v = n r t / p
v=lwh
To find the temperature when pressure is constant, you can use the ideal gas law equation, PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the gas constant, and T is temperature in Kelvin. You can rearrange the equation to solve for T: T = PV / nR.
v = -6
If v = r * h then> r = v / h
x/r=v x=vr
To solve for molar mass using the ideal gas law equation, you need to rearrange the equation to solve for molar mass, which gives you m = mRT/PV. Once you have the values for pressure (P), volume (V), temperature (T), and the gas constant (R), you can plug them into the equation to find the molar mass (m).
Using the ideal gas equation: PV=nRT, 0.52atm(V) = 12mol(0.0821)25k. Solve for V to get 47.4 liters.
v is -15... -15*2 = -30... -30+11= -19.
v=39 sqrt(v-3)=6 v-3=62=36 v=36+3=39
This is the general law of gases:PV = nRT (n is the number of moles)