p v = n r t v = n r t / p
v = -6
v is -15... -15*2 = -30... -30+11= -19.
H= v over pie r to the second
-7
P V = n R TDivide each side by ( n T ):(P V) / (n T) = R
p v = n r t v = n r t / p
v=lwh
To find the temperature when pressure is constant, you can use the ideal gas law equation, PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the gas constant, and T is temperature in Kelvin. You can rearrange the equation to solve for T: T = PV / nR.
v = -6
If v = r * h then> r = v / h
x/r=v x=vr
Using the ideal gas equation: PV=nRT, 0.52atm(V) = 12mol(0.0821)25k. Solve for V to get 47.4 liters.
To solve for molar mass using the ideal gas law equation, you need to rearrange the equation to solve for molar mass, which gives you m = mRT/PV. Once you have the values for pressure (P), volume (V), temperature (T), and the gas constant (R), you can plug them into the equation to find the molar mass (m).
v is -15... -15*2 = -30... -30+11= -19.
v=39 sqrt(v-3)=6 v-3=62=36 v=36+3=39
This is the general law of gases:PV = nRT (n is the number of moles)