k = pv/t. It is not possible to solve further with the information available.
Yes, because PV=nRt From this equation it becomes apparent that air pressure, V, can be negative. Since negative temperatures can exist, such as -30C (remember you have to use Celsius and not Fahrenheit). Thus we have negative numbers for air pressure.
PV ratio= contribution/sales*100
To solve this problem, several different steps must be taken. Convert Volume = 13*12*10 = 1560ft^3 * 28.2 = 43992L ~28.2 Litres per cubic ft Ideal Gas Equation: PV=nRT Rearrange: n=PV/RT Temperature:273+20=293K n=[(1*43992)/(0.0821*293) = 1828.78 1 mol Air Molecules = 6.022*10^23 Air Molecules 1828.78*(6.022*10^23) = 1.10 * 10^27
The following calculation is based on the following assumptions: 1. The composition of air is 78% Nitrogen, 20.95% O2 and 0.93% Ar. 2. Air is an ideal gas: i.e. Obeys the equaiton PV = nRT. The mass of 1 L of air at a pressure of 1 atmosphere and at 25oC is 1.18 g.
V=nRT/P
p v = n r t v = n r t / p
r is the constant 0.0821
From PV = nRT you solve for n (moles). Thus, n = PV/RT
From PV = nRT you solve for n (moles). Thus, n = PV/RT
Solve, using the Rule of 72 rate = 4%, years = 18, fv=$8,000. Solve for PV. Formula: PV = $1/(1+r) t PV = $8000/(1+.04) 18 PV = $8000/2.0258 3949.03 = $8000/2.20258
k = pv/t. It is not possible to solve further with the information available.
From PV = nRT you solve for n (moles). Thus, n = PV/RT
From PV = nRT you solve for n (moles). Thus, n = PV/RT
From PV = nRT you solve for n (moles). Thus, n = PV/RT
From PV = nRT you solve for n (moles). Thus, n = PV/RT
From PV = nRT you solve for n (moles). Thus, n = PV/RT