Q: Rectangle....p equals 2b plus 2h

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6h 8min

It is [(2a+2h+5) - (2a+5)]/h = 2h/h = 2

3h + (2h 20m) + 35m = (3+2)h + (20+35)m = 5h + 55m

Perimeter of a rectangle (P) = 2b+2h = 2*24+2h=114 48+2h=114 2h=66 h=33" Area of a rectangle (A) = b*h = 24*33= 1584 sq. in.

It is: 11h

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2h + 2h + 2h = 6h

6h 8min

(t+h)(x+2)

3h-5h + 11 = 17 is ------2h + 11 = 17- 11 -11____________-2h = 6___ ___-2 -2h = -3 (This is the answer.)

It is [(2a+2h+5) - (2a+5)]/h = 2h/h = 2

2Si +2HF-2siF + 2H

The complete ionic equation for this reaction is: 2H⁺(aq) + SO₄²⁻(aq) + Ca²⁺(aq) + 2I⁻(aq) → CaSO₄(s) + 2H⁺(aq) + 2I⁻(aq)

h = 0.538462 14 + 5h + 2h = 5h + 28h 14 + 7h = 33h 14 + 7h - 7h = 33h - 7h 14 = 26h 14/26 = 26/26h 0..538462 = h

Suppose base and height are b and h. 2b+2h=44 (the perimeter includes two bases and two widths) b=2b-11 base is 11 less than two times base Subtract b from both sides: 0=2b-11-b, b-11=0, b=11 2b=22 2b+2h=44, 22+2h=44, 2h=44-22=22, h=11 So the rectangle is a square with side 11.

No because it equals zero.

First set up the equation: 2h+10=40 Then get the variable alone by subtracting 10 from each side: 2h=30 And continue by dividing both sides by two 2h=30 ______ 2 2 h=15 So your answer is h=15

- 3h - 2h + 6h + 9 = h + 9