Yes, provided p = perimeter, b= breadth and h = height.
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6h 8min
It is [(2a+2h+5) - (2a+5)]/h = 2h/h = 2
3h + (2h 20m) + 35m = (3+2)h + (20+35)m = 5h + 55m
Perimeter of a rectangle (P) = 2b+2h = 2*24+2h=114 48+2h=114 2h=66 h=33" Area of a rectangle (A) = b*h = 24*33= 1584 sq. in.
It is: 11h