Subtract two.
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It is not. Suppose the function is "add 7".Then an input of 1 gives an output of 1+7 = 8.Double the input to 2 and the output is 2+7 = 9Whereas simply halving the output gives 9/2 = 4.5So the question is based on false premises.
The operation appears to involve subtracting 1 from the quotient of each input number divided by 5. Specifically, for each input number ( x ), the output can be calculated as ( \text{output} = \frac{x}{5} + 3 ). For example, for the input 5, the output is ( \frac{5}{5} + 3 = 4 ). This pattern holds for all given input numbers.
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9
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The rule appears to be a linear relationship between the input and output values. When the input increases by 4 (from 1 to 5), the output decreases by 4 (from 5 to 1). Similarly, when the input increases by another 4 (from 5 to 9), the output decreases by 4 again (from 1 to -3). Therefore, the rule seems to be that for every increase of 4 in the input, the output decreases by 4.
The rule used in this input-output relationship appears to be dividing the input numbers by 3 to get the corresponding output numbers. This can be deduced by observing that 3 divided by 3 is 1, 15 divided by 3 is 5, 18 divided by 3 is 6, and 27 divided by 3 is 9. Therefore, the rule is to divide the input numbers by 3 to obtain the output numbers.
It is not. Suppose the function is "add 7".Then an input of 1 gives an output of 1+7 = 8.Double the input to 2 and the output is 2+7 = 9Whereas simply halving the output gives 9/2 = 4.5So the question is based on false premises.
There are infinitely many possible answers. Rule 1: Add 9 to Input Rule 2: Add 5 to 2*Input Rule 3: Add 1 to 3*Input Rule 4: Subtract -3 from 4*Input or, moving away from whole numbers, Add 3.8 to 2.3 times Input.
There are many functions where if your input is -2 the output is 13. The simplest is probably just adding 15. You could also square -2 (to get 4) and then add 9.
L293D is having 20 pin IC and also 16 pin IC. description of 20 pin is: 1-enable 1 2- input 1 3- output 1 4,5,6,7,14,15,16,17- ground 8- output 2 9- input 2 10,20-vs 11-enable 2 12- input 3 13-output 3 18-output 4 19-input 4 description for 18 pin: 1-enable 1 2- input 1 3- output 1 4,5,12,13- ground 6-output 2 7- input 2 8,18-vs 9-enable 2 10-input 3 11-output 3 14-output 4 15-input 4
It is 9.
The operation appears to involve subtracting 1 from the quotient of each input number divided by 5. Specifically, for each input number ( x ), the output can be calculated as ( \text{output} = \frac{x}{5} + 3 ). For example, for the input 5, the output is ( \frac{5}{5} + 3 = 4 ). This pattern holds for all given input numbers.
this shows you everything you need about them Pin Number Description 1 A Input Gate 1 2 B Input Gate 1 3 Y Output Gate 1 4 A Input Gate 2 5 B Input Gate 2 6 Y Output Gate 2 7 Ground 8 Y Output Gate 3 9 B Input Gate 3 10 A Input Gate 3 11 Y Output Gate 4 12 B Input Gate 4 13 A Input Gate 4 14 Positive Supply
An input/output table works like this:You input something, and through a function, it outputs something else!Say I Had a function that is: input+2If I were to input 5, It would output 7All an input/output table does is displays a couple examples of multiple inputs with their outputs! Put tables only operate on one function....Example:Function: Input x 5 + 3INPUTS - OUTPUTS----------------------1 - 82 - 133 - 186 - 3310 - 53
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