20 yards
80
No. Distance is never negative, and total distance travelled doesn't decrease during a trip. The distance from A to B is the same as the distance from B to A. Displacement, on the other hand, can be negative, and can decrease during a trip. The displacement from A to B is the same magnitude, but opposite sign, as the displacement from B to A. An example would be if you went from your home to a friend's house 1 mile to the east. After you reach your friend's house, you have travelled a distance of 1 mile and your displacement from your starting position is 1 mile. When you come back home from your friends house, you travel a distance of 1 more mile. Your total distance travelled is now 2 miles, but your displacement from your starting location is zero (because you are back where you started.)
Since the car accelerates uniformly, its average speed during the interval is1/2 (initial speed + final speed) = 1/2 (4.15 + 17.11) = 10.63 m/s.The distance covered is (average speed) x (time) = (10.63) x (4.8) = 51.024 meters.If the motion during the 4.8 seconds was all in the same direction along a straight line,then that same 51.024 meters is also the displacement during that time.If, instead, it happened to take 4.8 seconds to go around a circle with a circumferenceof 51.024 m, then the displacement over the 4.8 seconds is zero, since the starting lineis also the finish line.
It is not the size of the gas tank, it is the displacement volume of all the cylinders during once cycle of all the cylinders put together.
around 4.
Sarah's total displacement can be found using the Pythagorean theorem. The horizontal displacement is 20 yards east, and the vertical displacement is 50 yards north minus 50 yards south, which equals 0. This means her total displacement is the square root of (20^2 + 0^2) = 20 yards.
20
The magnitude of Sara's total displacement can be found using the Pythagorean theorem. The total displacement is the square root of the sum of the squares of her displacements in each direction, which is √(50^2 + 20^2) = √(2500 + 400) = √2900 ≈ 53.85 yards.
The magnitude of his displacement during the walk is 40 meters. This means that the straight-line distance from his starting point to his final position is 40 meters.
Average velocity is the total displacement divided by the time interval during which the displacement occurred. It indicates the overall change in position over time and is a vector quantity that includes both magnitude and direction.
The displacement of an object during a specific unit of time is the change in its position from the initial point to the final point within that time frame. It is a vector quantity that includes both the magnitude (distance) and direction of the change. Displacement can be positive, negative, or zero depending on the direction of movement.
No, doubling an object's average speed does not always double the magnitude of its displacement. The displacement of an object also depends on the direction in which it travels. The relationship between speed and displacement is affected by the object's path and any changes in direction it makes during its journey.
The measurement of a wave's magnitude of oscillation is called amplitude. It represents the maximum displacement of a particle in a medium from its rest position during one complete wave cycle.
80
No. Distance can be greater than displacement, but not less. The magnitude of the displacement between two points is also the minimum possible distance of a path between the same points.However, the displacement can be zero if the distance is not if the object's starting point and ending point are the same.
3
The total is 3