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To simplify (9r^3 \div 4), you divide the coefficient 9 by 4 while keeping the variable (r^3) unchanged. This results in (\frac{9}{4}r^3). Therefore, (9r^3 \div 4 = \frac{9}{4}r^3).
That's not possible to simplify, or give an answer to, unless you know what 'r' is.
It simplifies to: 2s+4R
To find the number of 4-number combinations from the numbers 1 to 9, we use the combination formula ( C(n, r) = \frac{n!}{r!(n-r)!} ), where ( n ) is the total number of items to choose from and ( r ) is the number of items to choose. Here, ( n = 9 ) and ( r = 4 ). Thus, the number of combinations is ( C(9, 4) = \frac{9!}{4!(9-4)!} = \frac{9!}{4!5!} = 126 ). Therefore, there are 126 different 4-number combinations possible.
r + s = 4 and 2r + 3s = 8 multiply the first equation by 2 giving 2r + 2s = 8 subtract this from the second equation giving s = 0 So r = 4 and s = 0.
To simplify (9r^3 \div 4), you divide the coefficient 9 by 4 while keeping the variable (r^3) unchanged. This results in (\frac{9}{4}r^3). Therefore, (9r^3 \div 4 = \frac{9}{4}r^3).
That's not possible to simplify, or give an answer to, unless you know what 'r' is.
It simplifies to: 2s+4R
2r + 2s = 50 2r - s = 17 therefore 4r - 2s = 34 Add so that you can eliminate one of the variables: 2r + 2s = 50 4r - 2s = 34 ---------------- 6r + 0s = 84 Solve for r: 6r = 84 r = 14 Substitute r into one of the original equations: 2(14) + 2s = 50 28 + 2s = 50 2s = 22 s = 11 Doublecheck with the other original equation: 2(14) - 11 = 28 - 11 = 17
To find the number of 4-number combinations from the numbers 1 to 9, we use the combination formula ( C(n, r) = \frac{n!}{r!(n-r)!} ), where ( n ) is the total number of items to choose from and ( r ) is the number of items to choose. Here, ( n = 9 ) and ( r = 4 ). Thus, the number of combinations is ( C(9, 4) = \frac{9!}{4!(9-4)!} = \frac{9!}{4!5!} = 126 ). Therefore, there are 126 different 4-number combinations possible.
r + s = 4 and 2r + 3s = 8 multiply the first equation by 2 giving 2r + 2s = 8 subtract this from the second equation giving s = 0 So r = 4 and s = 0.
substitution
r = -36
1) 3S = R 2) R+6= 2 (S+6)= 2S+12 ----> R=2S+6 1,2 )--> 3S = 2S+6 ---> S=6 & R= 3 x 6 = 18 Ralph is 18 & Sara is 6 .
-13
2 scoops of raisins in Kellogg's raisin bran
since you do not know what r and s is all you need to write is... 2r + 2s the sum just simply means add them together.