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i341 + 3i89 - 2i122 + i5 - 6i1008 + i67 (I'm assuming that 'i' represents the imaginary square root of minus one.) If k is a multiple of 4: ik-3 = ik+1 = i ik-2 = ik+2 = -1 ik-1 = ik+3 = -i ik = 1 Using this: i341 = i and i89 = i i122 = -1and i5 = i i1008 = 1 and i67 = -i Therefore the expression can be written: i + 3i + 2 + i - 6 - i = 4i - 4 = 4(i-1)

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Q: Simplify i341 plus 3i89 minus 2i122 plus i5 minus 6i1008 plus i67 equals?
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