The only variable on the right hand side is sin(x). The maximum value of sin(x) is 1. So, the max value of 3sin(x) is 3*1 = 3 and so, the max value of 3sin(x) + 2 is 3+2 = 5.
(3sin(x)^2)(Cos(x))
You can't. You need 2 equations to solve for 2 unknowns
You cannot solve it since it is not a true equation.
divide 20 by 10 which equals 2 the times 2 by 2 which equals 4
The only variable on the right hand side is sin(x). The maximum value of sin(x) is 1. So, the max value of 3sin(x) is 3*1 = 3 and so, the max value of 3sin(x) + 2 is 3+2 = 5.
---- 2/3sin-1x
(3sin(x)^2)(Cos(x))
-2 plus 5 equals +3
You can't. You need 2 equations to solve for 2 unknowns
You cannot solve it since it is not a true equation.
divide 20 by 10 which equals 2 the times 2 by 2 which equals 4
2y = 4 (divide both sides by 2 to solve) y = 2
22
3
3
x=2