This equation is unsolvable without knowing one of the values of either x or y.
30-2=28 so 2x=28 28 divided by 2=14, so x is 14
subtraction; 80-y= 52. 28+52 =80
7 + 7 + 7 + 7 = 28
8x + 7 = 5x + 28 subtract 5x and 7 to both sides 3x = 21 divide by 3 to both sides x = 7
n = 28
Set up the equation and solve for z: 28 + z = 56 (next, subtract 28 from each side of the equaition to solve) z = 28
Without an equality sign the given terms can't be considered to be an equation and so therefore there is no solution.
This equation is unsolvable without knowing one of the values of either x or y.
There's nothing to solve. If it equaled something, you could solve it. For example, if x^2 - 28 = 0, then x = the square root of 28, which simplifies to plus or minus 2 times the square root of 7.
30-2=28 so 2x=28 28 divided by 2=14, so x is 14
subtraction; 80-y= 52. 28+52 =80
224
5 7 --- = ---- 3+1 6 ________________ 5 7 --- = --- 4 6 _______________ 4*7 = 5*6 28 = 30 28=/=30 False equation
11 x 2= 22 x+x=2 22 divided by 2= 11 22+11= 33 33-5=28
7 + 7 + 7 + 7 = 28
8x + 7 = 5x + 28 subtract 5x and 7 to both sides 3x = 21 divide by 3 to both sides x = 7