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The first step is to include the - or + values for the given terms
-2x-10y-12+3xy=4Put all x's to the other side and the ones with y's on the other:-10y+3xy=4+2x+12-10y+3xy=16+2xNow you factor a y from the side with the y's:y(-10+3x)=16+2xDivide both sides by (-10+3x):y=(16+2x)/(-10+3x)
2x+3xy-4y=10to solve for yyour objective will be to get y by itself on one side of the equal signyou first subtract 2x to get the terms with y variables on one side3xy-4y=10-2xthen undistribute the y from the two terms to get one yy(3x-4)=10-2xnow divide 3x-4y=(10-2x)/(3x-4)theres your answer
3xy2z
5x + 8xy + 10x + 3xy = 15x + 11xycombine like terms (the x's and the xy's)
3xy-4x + 15y-20 Sol: As there are no number are same. So -4x-3xy +15y-20 -------------------- -4x-3xy+15y-20
3xy - 3xy = 0
The first step is to include the - or + values for the given terms
18x3y5 + 9xy3 - 3xy = 3xy(6x2y4 + 3y2 - 1)
1,3,x,y,3x,3y,xy,3xy
3xy
2x + 5y = 2-3x - y = -3from the second equation:-y = -3 + 3xy = 3 - 3xsubstitute this value in the first equation:2x + 5(3-3x) = 22x + 15 - 15x = 2-13x + 15 = 2-13x = 2 - 15-13x = -13so, x = 1Now, solve for y :y = 3 - 3xy = 3 - 3 (1)y = zero
-2x-10y-12+3xy=4Put all x's to the other side and the ones with y's on the other:-10y+3xy=4+2x+12-10y+3xy=16+2xNow you factor a y from the side with the y's:y(-10+3x)=16+2xDivide both sides by (-10+3x):y=(16+2x)/(-10+3x)
3xy and 2xy. You can see that 3xy and 2xy have something in common with each other. They both have xy and the end of them. Hope this helped.
3xy + 3y2 = 3y (x + y)
4
2x+3xy-4y=10to solve for yyour objective will be to get y by itself on one side of the equal signyou first subtract 2x to get the terms with y variables on one side3xy-4y=10-2xthen undistribute the y from the two terms to get one yy(3x-4)=10-2xnow divide 3x-4y=(10-2x)/(3x-4)theres your answer