Area= base*height A=bh A hole= but+hole A=bh
bh=ws
V=Bh
YES!!! When calculating the area of a triangle the equation is A = (1/2)bh That is the base(b) is multiplied to the perpendicular height(h), and then multiplied by '1/2' or '0.5'.
A = 1/2 BH A = 24 = 1/2 BH 24 * 2 = BH 48 = BH H = B - 2 48 = B(B - 2) B2 - 2B = 48 B2 - 2B - 48 = 0 (B - 8)(B + 6) = 0 B = 8 or -6 Since the base cannot be negative, the base is 8 and the height is 6 (8 - 2)
b=Ah
2 is
a delta's a triangle, so the area of a triangle is bh/2
volume equals breadth times width
Dh / bh
The general idea in solving equations is to put the variable you want to solve for on the left side, and to take anything you don't need to the right side.A = (1/2) bhPut "h" to the right side:(1/2) bh = ATo get rid of 1/2, multiply both sides by 2:2 x (1/2) bh = 2 Abh = 2ATo get rid of the "b", divide both sides by "b";h = 2A
The rule for finding the area of a parallelogram is a simple equation of A=bh. For this equation, the A is area, b is base, and h is height. The area of a parallelogram is equal to the shape's base multiplied by the shape's height.
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The formula for finding the Area of a triangle is A = BH/2 (base x height divided by 2). Substitute the known dimensions to solve the equation: A = (B x H) ÷ 2 A = (3 x 5) ÷ 2 A = 15 ÷ 2 A = 7.5 sq cm
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