x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}
(2-r)e-rr
(4 ± i2) where i2 = -1
x2 + 13x = -30 ∴ x2 + 13x + 30 = 0 ∴ (x + 3)(x + 10) = 0 ∴ x ∈ {-3, -10}
x2 + 7x = 0 => x*(x + 7) = 0 => x = 0 or x + 7 = 0 so that x = 0 or x = -7
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}
x: x2 - 81 = 0
x=4 x=0
(2-r)e-rr
(4 ± i2) where i2 = -1
x2 + 13x = -30 ∴ x2 + 13x + 30 = 0 ∴ (x + 3)(x + 10) = 0 ∴ x ∈ {-3, -10}
x2 + 6x + 8 = 0 Solve for x.X = -2 or X = -4
x2 + 7x = 0 => x*(x + 7) = 0 => x = 0 or x + 7 = 0 so that x = 0 or x = -7
A quadratic equation. If you wish to solve for x, you can do so as follows: -x2 + 6x + 7 = 0 x2 - 6x - 7 = 0 (x - 7)(x + 1) = 0 x ∈ {-1, 7}
x2-13x+36=(x-9)(x-4)=0 x=9 or x=4
144X = X2 144X - X2 = 0 (144 - X)X = 0 X = 0 or X = 144