k can be 2 or -2. A binomial squared is: (a + b)² = a² + 2ab + b² Given x² - 5kx + 25 = (a + b)² = a² + 2ab + b² we find: a² = x² → a = ±x 2ab = -5kx b² = 25 → b = ±5 If we let a = x, then: 2ab = 2xb = -5kx → 2 × ±5 = -5k → k = ±2 If k = 2 then the binomial is (x - 5)² If k = -2 then the binomial is (x + 5)² To be complete if a = -x, then: If k = 2 then the binomial is (-x + 5)² If k = -2 then the binomial is (-x - 5)² which are the negatives of the binomials being squared.
As a binomial it is, surprisingly, x + 3.
(x - 5)(x - 8)
(x - 1)(3x + 5)
5 - x^2 = (the square root of 5 minus x)(the square root of 5 plus x)
k can be 2 or -2. A binomial squared is: (a + b)² = a² + 2ab + b² Given x² - 5kx + 25 = (a + b)² = a² + 2ab + b² we find: a² = x² → a = ±x 2ab = -5kx b² = 25 → b = ±5 If we let a = x, then: 2ab = 2xb = -5kx → 2 × ±5 = -5k → k = ±2 If k = 2 then the binomial is (x - 5)² If k = -2 then the binomial is (x + 5)² To be complete if a = -x, then: If k = 2 then the binomial is (-x + 5)² If k = -2 then the binomial is (-x - 5)² which are the negatives of the binomials being squared.
As a binomial it is, surprisingly, x + 3.
(x - 5)(x - 8)
x+50
(x - 1)(3x + 5)
5 - x^2 = (the square root of 5 minus x)(the square root of 5 plus x)
There is no sensible expansion of 3x + 4√5
x2-12x+35 = (x-5)(x-7)
It is: x^2 -9
It depends entirely on the value of x.
It is a binomial expression in X and Y.
Yes, specifically a binomial.