(2x-5) (x-1)
(x + 5)(x + 1)
the only thing you can do to this is factor it... (x + 5)(x + 5) x=-5
x2 + 10y + 25 doesn't factor neatly. If that was x2 + 10x + 25, it would factor to (x + 5)(x + 5) or (X + 5)2
(x + 3)(x + 3)
(2x-5) (x-1)
x2 + 5x + not really sure what that extra plus is for... this is the most you can factor it... x(x + 5)
(x + 5)(x + 1)
the only thing you can do to this is factor it... (x + 5)(x + 5) x=-5
x2 + 10y + 25 doesn't factor neatly. If that was x2 + 10x + 25, it would factor to (x + 5)(x + 5) or (X + 5)2
X^2 + 5 doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: 0 plus or minus i times the square root of 5.x = 0 + 2.23606797749979ix = 0 - 2.23606797749979iwhere i is the square root of negative one.
(x + 15)(x + 5)
(x + 5)(x + 8)
(x + 3)(x + 3)
That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: (-5 plus or minus the square root of -15) divided by 2.x = -2.5 + 1.9364916731037085ix = -2.5 - 1.9364916731037085iwhere i is the square root of negative one.
(x + 3)(4x + 5)
(x + 1)(3x + 5)